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3 years ago

State the degree for the polynomial:

Mathematics

2 answers:

Ivahew [28]3 years ago

7 0

Answer:

Step-by-step explanation:

the degree of the polynomial is the highest degree of any of the terms.

Papessa [141]3 years ago

6 0

4 it’s because the person on the top said it

You might be interested in

Select all that apply.

vfiekz [6]

Answer:

1/3 , 4/15 , 5/6

Step-by-step explanation:

All you have to do is plug the fractions in your calculator and you see that 1/3, 4/15, and 5/6 are repeating, but the others stop after only a couple of decimal places.

Hope this helps!

4 0

3 years ago

4x+8y=-4<br> -5x + 3y=-21<br> (3-2)

cricket20 [7]

Answer:

x + 2y + 1 = 0

-5x+3y-21 = 0

(3-2) = 1

5 0

3 years ago

For what value of constant c is the function k(x) continuous at x = 0 if k =

nlexa [21]

The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x) is continuous, we take the limit of the parameter as follows:

$\mathbf{ \lim_{x \to 0^-} k(x) = \lim_{x \to 0^+} k(x) = 0 }$

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= c }$

Provided that:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }$

Using l'Hospital's rule:

$\mathbf{\implies \lim_{x \to 0} \ \ \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}= \lim_{x \to 0} sec \ x \ tan \ x = 0}$

Therefore:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}=0 }$

Hence; c = 0

Learn more about the limit of a function x here:

brainly.com/question/8131777

#SPJ1

5 0

2 years ago

A group of farmers planted 5 fields of vegetables. Of the fields they planted, 1/2 were planted with cabbage. How many fields of

Zolol [24]

Answer:

Total number of fields of vegetables = 62

Step-by-step explanation:

8 0

2 years ago

A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f

tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

= 180° - (45° + 120°)

= 180° - 165°

= 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

$\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}$

$\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}$

$\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}$

PR = $\frac{12\text{sin}(120)}{\text{sin}(15)}$

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

8 0

3 years ago