Answer:
time=4, answer choice A
time=5.5, answer choice B
Explanation:
This is taken from the kinematic equation, v=vo+(1/2)at^2
Velocity at time 4 = 30+(2.5)(4)^2
Velocity at time 5.5 = 30+(2.5)(5.5)^2
Velocity at time 4 seconds = 70 m/s
Velocity at time 5.5 seconds = 105.63 m/s
A body of mass 2kg is at rest. A force of 20N makes it move with a velocity of 5m/s, the impulse of the body would be 10 Kgm/s
<h3>What is impulse?</h3>
The product of the average applied force and the time for which it is exerted is known as an impulse. The unit for the impulse of force is the same as that of momentum which is kg*m/s
The mathematical relation for impulse is
Impulse = F * Δt =change in momentum
As given in the problem body of mass of 2 kg is at rest. A force of 20N makes it move with a velocity of 5m/s
Change in the momentum of the body
Δm = m(v₂-v₁)
As the body was initially at rest v₁ =0
Δm = 2×5
Δm = 10 Kgm/s
As we know that change in the momentum represents the impulse of the force
Thus, the impulse of the body would be 10 Kgm/s
Learn more about impulse, here
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The answer is 21m because the motion is in one dimension with constant acceleration.
The initial velocity is 0, because it started from rest, the acceleration <span>ax</span> is <span>4.7<span>m<span>s2</span></span></span>, and the time t is <span>3.0s</span>
Plugging in our known values, we have
<span>Δx=<span>(0)</span><span>(3.0s)</span>+<span>12</span><span>(4.7<span>m<span>s2</span></span>)</span><span><span>(3.0s)</span>2</span>=<span>21<span>m</span></span></span>
Answer:
Emissions per second = 0.36
Explanation:
Please find the attached question
Solution
Given
Let X be the rate of background emission.
X = B/t
Where B = 36
And t = 100
X = 36/100 = 0.36
Answer: 5 m, 2 s
Explanation:
gravity is roughly 10 m/s²downward
That means in one second, the velocity will have been reduced to zero
The average speed is (10 + 0) / 2 = 5 m/s
h = vt = 5(1) = 5 m
It will take as long to fall back to the thrower from rest so total flight is 1 + 1 = 2 s