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4 years ago

8

Can you differentiate between the wavelength of visible light and the wavelength of a moving soccer ball

2 answers:

KIM [24]4 years ago

7 0

Answer

The wavelength of a moving soccer ball is invisible using the naked eye.

Explanation

The wavelength of a moving soccer ball is not detectable with the naked eye because it is smaller than the wavelength of visible light. The human eye is only able to see about 17 frames per second. The wavelength of a moving soccer ball can be compared to the infinite value of the de Broglie wavelength where the Plank’s constant is so small.

natulia [17]4 years ago

5 0

A dramatic difference. Moving soccer ball does not have any wavelength. It's not a wave process at all.

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How long does it take Larry to run 200 meters running at a speed of 21 m/s

andreev551 [17]

Answer:

9.52 seconds

Explanation:

t = d/v

t = 200 / 21

t = 9.52s (to 3 s.f.)

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2 years ago

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What happens to atomic numbers as you follow a period across the periodic table

geniusboy [140]

Answer:

As you move across a period, the atomic mass increases because the atomic number also increases

Explanation:

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3 years ago

1. A plane flying a triangular patter flies 150 km[N], then 400 km(E). What is the total displacement of the

zhenek [66]

Answer:

1. The displacement is 427.2 km.

Explanation:

1. A = 150 km North

B = 400 km East

The net displacement is given by

$R =\sqrt{400^2 + 150^2 }\\\\R = 427.2 km$

6 0

3 years ago

Suppose you have a 0.750-kg object on a horizontal surface connected to a spring that has a force constant of 150 N/m. There is

marshall27 [118]

Answer:

$x=0.0049\ m= 4.9\ mm$

$d=0.01153\ m=11.53\ mm$

Explanation:

Given:

mass of the object, $m=0.75\ kg$

elastic constant of the connected spring, $k=150\ N.m^{-1}$

coefficient of static friction between the object and the surface, $\mu_s=0.1$

(a)

Let x be the maximum distance of stretch without moving the mass.

<em>The spring can be stretched up to the limiting frictional force 'f' till the body is stationary.</em>

$f=k.x$

$\mu_s.N=k.x$

where:

N = m.g = the normal reaction force acting on the body under steady state.

$0.1\times (9.8\times 0.75)=150\times x$

$x=0.0049\ m= 4.9\ mm$

(b)

Now, according to the question:

Amplitude of oscillation, $A= 0.0098\ m$

coefficient of kinetic friction between the object and the surface, $\mu_k=0.085$

Let d be the total distance the object travels before stopping.

<em>Now, the energy stored in the spring due to vibration of amplitude:</em>

$U=\frac{1}{2} k.A^2$

<u><em>This energy will be equal to the work done by the kinetic friction to stop it.</em></u>

$U=F_k.d$

$\frac{1}{2} k.A^2=\mu_k.N.d$

$0.5\times 150\times 0.0098^2=0.0850 \times 0.75\times 9.8\times d$

$d=0.01153\ m=11.53\ mm$

<em>is the total distance does it travel before stopping.</em>

7 0

3 years ago

What does this mean??

Fudgin [204]

I need help on this too lol

7 0

3 years ago