To solve this problem we need the concepts of Energy fluency and Intensity from chemical elements.
The energy fluency is given by the equation
![\Psi=4RcE\pi](https://tex.z-dn.net/?f=%5CPsi%3D4RcE%5Cpi)
Where
The energy fluency
c = Activity of the source
r = distance
E = electric field
In the other hand we have the equation for current in materials, which is given by
![I= I_0 e^{-\mu_{h20}X_{h2o}} e^{-\mu_{Fe}X_{Fe}}](https://tex.z-dn.net/?f=I%3D%20I_0%20e%5E%7B-%5Cmu_%7Bh20%7DX_%7Bh2o%7D%7D%20e%5E%7B-%5Cmu_%7BFe%7DX_%7BFe%7D%7D)
Then replacing our values we have that
![I = 1*10^{-3} * 3.3*10^{10} * e ^{-0.06*1.1} e^{-0.058*7.861}](https://tex.z-dn.net/?f=I%20%3D%201%2A10%5E%7B-3%7D%20%2A%203.3%2A10%5E%7B10%7D%20%2A%20e%20%5E%7B-0.06%2A1.1%7D%20e%5E%7B-0.058%2A7.861%7D)
![I = 1.3*10^7 Bq](https://tex.z-dn.net/?f=I%20%3D%201.3%2A10%5E7%20Bq)
We can conclude in this part that 1.3*10^7Bq is the activity coming out of the cylinder.
Now the energy fluency would be,
![\Psi = \frac{cE}{4\pir^2}](https://tex.z-dn.net/?f=%5CPsi%20%3D%20%5Cfrac%7BcE%7D%7B4%5Cpir%5E2%7D)
![\Psi = \frac{1.3*10^7*2*1.25}{4\pi*11^2}](https://tex.z-dn.net/?f=%5CPsi%20%3D%20%5Cfrac%7B1.3%2A10%5E7%2A2%2A1.25%7D%7B4%5Cpi%2A11%5E2%7D)
![\Psi = 2.14*10^4 MeV/cm^2.s](https://tex.z-dn.net/?f=%5CPsi%20%3D%202.14%2A10%5E4%20MeV%2Fcm%5E2.s)
The uncollided flux density at the outer surface of the tank nearest the source is ![\Psi = 2.14*10^4 MeV/cm^2.s](https://tex.z-dn.net/?f=%5CPsi%20%3D%202.14%2A10%5E4%20MeV%2Fcm%5E2.s)
<span>Answer:
I'm pretty sure the SA / V ratio would get smaller. Assume that the cell is more or less spherical. SA = 4(pi)r^2, while V = (3/4)(pi)r^3. The ratio = (4(pi)r^2)/((3/4)(pi)r^3), which can be simplified to 3/r. Thus, the larger r gets, the smaller the ratio becomes.</span>
Answer:
Driver hits the dog
Explanation:
From kinematics equation
and making a the subject
![a=\frac {v_f^{2}-v_i^{2}}{2s}=\frac {0-20^{2}}{2*50}=-4m/s^{2}](https://tex.z-dn.net/?f=a%3D%5Cfrac%20%7Bv_f%5E%7B2%7D-v_i%5E%7B2%7D%7D%7B2s%7D%3D%5Cfrac%20%7B0-20%5E%7B2%7D%7D%7B2%2A50%7D%3D-4m%2Fs%5E%7B2%7D)
F=ma=800*-4=-3200 N
The driver is required to apply a force of 3200 N to effectively not hit the dog. However, when the driver applies 2000 N, this is less the required force by 1200 N hence the driver hits the dog.
True, because people should reach their full potential within themselves and human psychologist should help those that need help to reach it.