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galina1969 [7]
3 years ago
9

The student council needs 2/3 of its members to vote favorably for a motion in order for it to pass. currently, 2/7 of the membe

rs are in favor of the motion. what additional fraction of the council needs to be favor of the motion in order for it pass?
Mathematics
1 answer:
AfilCa [17]3 years ago
3 0

Answer:

8/21

Step-by-step explanation:

First, we need to have like denominators.

3*7=21

2/3= 14/21

2/7= 6/21

14-6=8

Answer: 8/21

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Determine whether each expression is equivalent to 49^2t – 0.5.
vampirchik [111]

Answer:

None of the expression are equivalent to 49^{(2t - 0.5)}

Step-by-step explanation:

Given

49^{(2t - 0.5)}

Required

Find its equivalents

We start by expanding the given expression

49^{(2t - 0.5)}

Expand 49

(7^2)^{(2t - 0.5)}

7^2^{(2t - 0.5)}

Using laws of indices: (a^m)^n = a^{mn}

7^{(2*2t - 2*0.5)}

7^{(4t - 1)}

This implies that; each of the following options A,B and C must be equivalent to 49^{(2t - 0.5)} or alternatively, 7^{(4t - 1)}

A. \frac{7^{2t}}{49^{0.5}}

Using law of indices which states;

a^{mn} = (a^m)^n

Applying this law to the numerator; we have

\frac{(7^{2})^{t}}{49^{0.5}}

Expand expression in bracket

\frac{(7 * 7)^{t}}{49^{0.5}}

\frac{49^{t}}{49^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{49^{t}}{49^{0.5}} becomes

49^{t-0.5}}

This is not equivalent to 49^{(2t - 0.5)}

B. \frac{49^{2t}}{7^{0.5}}

Expand numerator

\frac{(7*7)^{2t}}{7^{0.5}}

\frac{(7^2)^{2t}}{7^{0.5}}

Using law of indices which states;

(a^m)^n = a^{mn}

Applying this law to the numerator; we have

\frac{7^{2*2t}}{7^{0.5}}

\frac{7^{4t}}{7^{0.5}}

Also; Using law of indices which states;

\frac{a^{m}}{a^n} = a^{m-n}

\frac{7^{4t}}{7^{0.5}} = 7^{4t - 0.5}

This is also not equivalent to 49^{(2t - 0.5)}

C. 7^{2t}\ *\ 49^{0.5}

7^{2t}\ *\ (7^2)^{0.5}

7^{2t}\ *\ 7^{2*0.5}

7^{2t}\ *\ 7^{1}

Using law of indices which states;

a^m*a^n = a^{m+n}

7^{2t+ 1}

This is also not equivalent to 49^{(2t - 0.5)}

6 0
4 years ago
Whar does7^or other numbers like it mean?
likoan [24]
7^0=1

7^1=7

7^2=7*7=49

7^3=7*7*7=343

etc... etc...
4 0
3 years ago
Read 2 more answers
Norman bought 5/6 pounds of cookies. He ate 3/5 cookies. What was the weight of the cookies he ate
insens350 [35]

Answer:

Step-by-step explanation:

5/6 pounds he ate 3/5 =0.23

4 0
3 years ago
Find the value of cos C rounded to the nearest hundredth, if necessary
Sindrei [870]

\bold{\frac{5}{13} or 0.38}

Answer:

Solution given:

here

by using Pythagoras law

hypotenuse =

\displaystyle\sqrt{adjacent ²+opposite ²}\\=\sqrt{15²+36²}=39

Cos C=\frac{adjacent} {hypotenuse}=\frac{15}{39}=\frac{5}{13} or{0.38}

6 0
3 years ago
How do you write 30 feet to 60 feet as a fraction and in lowest terms
Arte-miy333 [17]
I think the answer would be 1/2
8 0
4 years ago
Read 2 more answers
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