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algol [13]
3 years ago
12

PLEASSSEEEE HELPPPPPP !!!!!

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
5 0
Marking the questions as 12345.
1 is G, 2 is E, 3 is D, 4 is C, and 5 is A. But I might be misunderstanding this too.
Bogdan [553]3 years ago
5 0

Answer:

The answer to your question is:

Step-by-step explanation:

∠ 2   ≅  ∠ 5

∠ 7   ≅  ∠ 9

∠ 11  ≅  ∠ 13

∠ 12 ≅ ∠ 14

∠1    ≅ ∠ 4

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Doug bought a new car for 25,
pentagon [3]
This is exponential decay which can be expressed as:

y=ab^t, y=final value, a=initial value, b=rate, t=time

In this case a=25000, r=(100-20)/100=0.8 so

y=25000(0.8^t), so in 4.5 years...

y=25000(0.8^4.5)

y≈$9158.93  (to nearest cent)
3 0
3 years ago
Read 2 more answers
-3(2x^2+ax+b)=-6x+12x-15 what is the value of a and b
bonufazy [111]
B= -2x+5-2x^2-ax
A= -2x+5-2x^2-b/x 
x=0

5 0
3 years ago
Please help me with this
PolarNik [594]

Answer:

Okay the answer is

6 0
3 years ago
Read 2 more answers
GIVING BRAINLIEST!!!PLS HELP!! :((
zhannawk [14.2K]
6,702 = 6 thousands and 7 hundreds and 0 tens and 2 ones
= 6 × 1000 + 7 × 100 + 0 × 10 + 2 × 1
= 6000 + 700 + 2.

Above, we have written the number 6,702 in expanded form, or as a SUM of its different parts according to place value.The digit 6 in the number 6,702 actually has the value 6,000 and the digit 7 actually signifies the value 700. This is why our number system is also called a place value system, because the value of a digit (like 6 or 7 in our example) depends on its placement within the number. In other words, the digit 6 in 6702 does not mean six but six thousand, because the six is placed in the thousands' place. The place of a digit determines its value. I'll go for 66.04 that's the closest
7 0
3 years ago
Show that if the vector field F = Pi + Qj + Rk is conservative and P, Q, R have continuous first-order partial derivatives, then
olchik [2.2K]

Answer:

It is proved that \frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}

Step-by-step explanation:

Given vector field,

F=P\uvec{i}+Q\uvec{j}+R\uvec{k}

Where,

P=f_x=\frac{\partial f}{\partial x}, Q=f_y=\frac{\partial f}{\partial y}, R=f_z=\frac{\partial f}{\partial z}

To show,

\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}

Consider,

\frac{\partial P}{\partial y}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial y\partial x}=\frac{\partial^2 f}{\partial x\partial y}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial y})=\frac{\partial Q}{\partial x}

\frac{\partial P}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial z\partial x}=\frac{\partial^2 f}{\partial x\partial z}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial x}

\frac{\partial Q}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial y})=\frac{\partial^2 f}{\partial z\partial y}=\frac{\partial^2 f}{\partial y\partial z}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial y}

Hence proved.

4 0
3 years ago
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