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algol [13]
3 years ago
12

PLEASSSEEEE HELPPPPPP !!!!!

Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
5 0
Marking the questions as 12345.
1 is G, 2 is E, 3 is D, 4 is C, and 5 is A. But I might be misunderstanding this too.
Bogdan [553]3 years ago
5 0

Answer:

The answer to your question is:

Step-by-step explanation:

∠ 2   ≅  ∠ 5

∠ 7   ≅  ∠ 9

∠ 11  ≅  ∠ 13

∠ 12 ≅ ∠ 14

∠1    ≅ ∠ 4

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PLEASE HELP GUYS I’m being timed
fomenos

<em><u>The question is the base of the triangle, so we use the formula : b²=c²–a²</u></em>

——————————————————————

<u>{b}^{2}  =  \sqrt{c^{2} -  {a}^{2} }</u>

<u>{b}^{2}  =  \sqrt{ {16}^{2} -  {8}^{2} }</u>

<u>{b}^{2} =  \sqrt{256 - 64}  =  \sqrt{192}</u>

<u>\sqrt{192}  =8 \sqrt{3}</u>

5 0
3 years ago
Compute the area of the triangle height equals 6 cm base equals 12 cm what is the area
Aliun [14]

AREA =1/2 × base × height = 1/2×6×12=36cm^2

HOPE THIS WILL HELP U

3 0
3 years ago
A credit card company is about to send out a mailing to test the market for a new credit card. From that sample, they want to es
Sergeeva-Olga [200]

Answer:

n=\frac{0.005(1-0.005)}{(\frac{0.001}{1.96})^2}=19111.96  

And rounded up we have that n=19112

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.001 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.005(1-0.005)}{(\frac{0.001}{1.96})^2}=19111.96  

And rounded up we have that n=19112

3 0
3 years ago
Read 2 more answers
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D.(-1,4)..............
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I don’t know the question isn’t making any sense at least to me
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