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Luden [163]
3 years ago
5

Divide (16x6 − 12x4 + 4x2) by 4x2.

Mathematics
1 answer:
Degger [83]3 years ago
6 0
We know that
<span>(16x6 − 12x4 + 4x2) / 4x2
is equal to
[16x6/4x2]+[-12x4/4x2]+[4x2/4x2]
=[4x4]+[-3x2]+[1]
=4x4-3x2+1

the answer is
</span>4x4-3x2+1<span>

</span>
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J= -2(3-k) make k the subject
lapo4ka [179]

Answer:

K=J+6/2

Step-by-step explanation:

J= -2(3-k)

simplify whats in the bracket

J= -6+2k

J+6=2k

Divide both sides by 2

J+6/2=2k/2

2 and 2 will cancel out

remaining K

So, Therefore K=J+6/2

Hope it Helped

3 0
2 years ago
Simplify 7 + (−3). Please hurry<br><br> -10<br> -4<br> 4<br> 10
Viefleur [7K]

Answer: The answer is 4. 7+(-3) is like 7 minus 3.

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Two fair number cubes ate rolled. their sum is greater than 10 and one of the number is 6 which of the following best describes
Inga [223]
The answer is B not mutually exclusive
7 0
3 years ago
A random sample of 77 fields of corn has a mean yield of 26.226.2 bushels per acre and standard deviation of 2.322.32 bushels pe
PSYCHO15rus [73]

Answer:

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

Step-by-step explanation:

n = 77

mean u = 26,226.2  bushels per acre

standard deviation s = 2,322.32

let E = true mean

let A = test statistic

Find 95% Confidence Interval

so

let  A =  (u - E) *  (\sqrt{n}  / s)   be the test statistic

we want      P( average_l <  A  < average_u )  = 95%

look for  lower 2.5%  and the upper 97.5%  Because I think this is a 2-tail test

average_l =  -1.96  which corresponds to the 2.5%

average_u = 1.96

P(  -1.96  <  A  <  1.96)  =  95%

P(  -1.96  <  (u - E) *  (\sqrt{n}  / s)  <  1.96)  =  95%

Solve for the true mean E ok

E   <   u + 1.96* (s  / \sqrt{n})

from  -1.96  <  (u - E) *  (\sqrt{n}  / s)

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  518.7197348105429466

upper bound is 26,744.9197

or

u - 1.96* (s  / \sqrt{n})  < E

26,226.2 -  518.7197348105429466  < E

25,707.48026519  < E

lower bound is 25,707.48026519

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

7 0
3 years ago
(3t^2+1)-t^2. How do you do this equation and what’s the answer. Algebra 1.
Oksana_A [137]

2t^2+1

Subtract t^2 from 3t^2 you get 2t^2

which is 2t^2+1 answer

3 0
3 years ago
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