D I did this question a while back
Answer:
Step-by-step explain
Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :
A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)
If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.
For the given function, there is no horizontal asymptote.
We can find the slant asymptote by using long division:
(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))
The slant asymptote is y=3/2x+3/4
Answer:
8+7x+4y
Step-by-step explanation:
15-7 is 8
12x-5x is 7
Put it all together to get 8+7x+4y
Answer:
1579
Step-by-step explanation:
There is a particular formula you must use and it leads to this 420(1 + 0.18)^8=1579
Answer:
36
Step-by-step explanation:
Area of total region = 12 ×5
=60
Area of the small region = 8×3
=24
Area of shaded region = Area of Total region - area of small region
= 60 - 24
= 36
