
In order to be differentiable everywhere,
must first be continuous everywhere, which means the limits from either side as
must be the same and equal to
. By definition,
, and


so we need to have
.
For
to be differentiable at
, the derivative needs to be continuous at
, i.e.

We then need to have

Then

Answer:
{2, 4, 6}
Step-by-step explanation:
the domain is the interval or set of valid x (input) values.
the range is the interval or set of valid y (result) values.
all we need to do is use the given x values in the functional definition and collect the result values. that is the range.
x = -1
y = 2×-1 + 4 = 2
x = 0
y = 2×0 + 4 = 4
x = 1
y = 2×1 + 4 = 6
<span>Divide 12% by 12 months to get 1% per month. Multiply by 2 months to get 2%. Multiply 1800 by 0.02 </span>
Answer:
Step-by-step explanation:
(0, -9) and (3,3)
(3+9)/(3-0) = 12/3 = 4
y + 9 = 4(x - 0)
y + 9 = 4x - 0
y = 4x - 9