Answer:
See below
Explanation:
100 km / 45 km/hr = 2.222 hr
100 km / 30 km/hr =3.3333 hr
Difference = 1.111 hr = 1 hr 6 2/3 min
I believe the coma is formed from the dust and gas from a comet.
Hope this helps!! :)
6.3^2 + 12^2 = thirteen.6^2. Left hand area balances suitable hand area! The triangle with factors 6.3 cm, 12 cm and thirteen.6 cm is nice-angled. Makes issues easier. Draw a triangle XYZ with XY = 6.3 cm, YZ = 12 cm and XZ = thirteen.6 cm (the hypotenuse) --- on a sheet of paper. be conscious that XY and YZ has a suitable perspective between them. Circle X and Y. that's the place there are 2 currents of length 15.0 A coming into the web site frequently. The magnetic field located at factor located at a distance R far flung from an prolonged straight away cutting-edge I is given by way of B = (mu-nought)*(I) / (2*pi*R) “mu-nought” is (4*pi*10^-7), so B = (2I)/R the two currents make magnetic fields B1 and B2 at Z, so as that they are at suitable angles with XZ and YZ respectively. the attitude between B1 and B2 is theta, the place theta is likewise the attitude at Z in triangle XYZ. Theta is rather discovered through fact all 3 factors of XYZ are prevalent, making use of easy sin, tan or cos. Draw a parallelogram with 2 arrows for factors, of length B1 and B2, with the attitude theta between them. locate the diagonal of the parallelogram between B1 and B2, and the attitude it makes with B1. for this reason you be responsive to that's the dimensions and path of the ensuing field. ok, right this is the place physics ends, something is arithmetic. It’s as much as you presently to the two draw to scale or calculate.
To solve this problem we will apply the mathematical consideration of the electric field on an axial axis of a ring. This definition is already established mathematically and is a subordinate of the definition of the magnetic field of Coulomb's laws. It can be expressed as,
Here,
k = Coulomb's constant
Q = Charge
x = Distance on the axial line
R = Radius of the circle or ring
At x = 1 cm, we have that the total charge is 66.0 μC and the radius 0.1m, then replacing,
Therefore the electric field on the axis of the ring is 5.85MN/C