Question

Bats use sound to sense objects by sending out short ultrasound pulses and listening for the echo off the object. A. Sketch the ultrasound pulse leaving the bat, reflecting off the object and returning to the bat. B. If a stationary bat is 43 m from an object, how much time elapses between when the bat emits the pulse and it hears the echo

Answer 1

Answer:

B. t = 0.250s

Explanation:

A. An image with the sketch of the bat emitting a sound, which reflects on a surface and return to the bat is attached below.

B. In order to calculate the time that the pulse emitted by the bat, return to the bat, you first calculate the time that pulse takes to arrive to the object.

You use the following formula:

$x=vt$      (1)

x: distance to the object = 43m

t: time = ?

v: speed of sound beat = 343 m/s  

You solve the equation (1) for t:

$t=\frac{x}{v}=\frac{43m}{343m/s}=0.125s$

The time on which the bat hears the echo is twice the value of t, that is:

$t'=2(0.125s)=0.250s$

The time on which bat heart the echo of its sound, from the moment on which bat emitted it, is 0.250s