Answer:
Pressure at the entrance of pipe is 2.68 x 10⁵ Pa
Explanation:
Given :
Density of liquid, ρ = 1103 kg/m³
Speed of liquid at entrance of pipe, v₁ = 1.37 m/s
Diameter of pipe at entrance, d₁ = 0.19 m
Diameter of pipe at exit, d₂ = 0.05 m
Height difference between pipe, h = 6.34 m
Pressure of liquid at the exit of pipe, P₂ = 1.2 atm
Acceleration due to gravity, g = 9.8 m/s²
Consider A₁ and A₂ be the area of pipe at entrance and exit of pipe respectively, and v₂ be the speed of liquid at exit of pipe.
Applying equation of continuity,
A₁v₁ = A₂v₂
But and , so the above equation becomes:
Substitute the suitable values in the above equation.
v₂ = 19.78 m/s
Consider P₁ be the pressure of the liquid at the entrance of the pipe.
Applying Bernoulli's equation:
Energy per unit volume before entering = Energy per unit volume after leaving
Substitute the suitable values in the above equation.
P₁ = 2.68 x 10⁵ Pa