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solmaris [256]
3 years ago
9

How many charges do copper(II) and Carbide have?

Physics
2 answers:
krok68 [10]3 years ago
7 0
10 is the answer of how many charges copper and carbide have.
lapo4ka [179]3 years ago
5 0

Answer:They have 10

Explanation:

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Two identical cars A and B are at rest on a loading dock with brakes released. Car C, of a slightly different style but of the s
Nadusha1986 [10]

Answer:

Explanation:

Let the velocity after first collision be v₁ and v₂ of car A and B . car A will bounce back .

velocity of approach = 1.5 - 0 = 1.5

velocity of separation = v₁ + v₂

coefficient of restitution = velocity of separation / velocity of approach

.8 = v₁ + v₂ / 1.5

v₁ + v₂ = 1.2

applying law of conservation of momentum

m x 1.5 + 0 = mv₂ - mv₁

1.5 = v₂ - v₁

adding two equation

2 v ₂= 2.7

v₂ = 1.35 m /s

v₁ = - .15 m / s

During second collision , B will collide with stationary A . Same process will apply in this case also. Let velocity of B and A after collision be v₃ and v₄.

For second collision ,

coefficient of restitution = velocity of separation / velocity of approach

.5 = v₃ + v₄ / 1.35

v₃ + v₄ = .675

applying law of conservation of momentum

m x 1.35 + 0 = mv₄ - mv₃

1.35 = v₄ - v₃

adding two equation

2 v ₄= 2.025

v₄ = 1.0125 m /s

v₃ = - 0 .3375  m / s

3 0
4 years ago
Two asteroids are 75000 m apart one has a mass of 8 x 10^7 kg if the force of gravity between them is 1.14 what is the mass of t
vaieri [72.5K]
I’m going to say B

I hope this helped
4 0
3 years ago
Read 2 more answers
If a girl is standing still and holding a box, is she doing any work? (No)
SpyIntel [72]

Answer:

gravity

Explanation:

7 0
3 years ago
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The formulas into H2O and CO2 are present molecules which are defined as
NNADVOKAT [17]
H2O is water
CO2 is carbon dioxide
3 0
3 years ago
A 20kg rock is sliding on a rough, horizontal surface at 8 m/s and eventually stops due to friction. the coefficient of kinetic
Dmitry_Shevchenko [17]

Answer:

156watts

Explanation:

M = 20

U = 0.200

Vo = 8.0

We are to get p

P = w/t

W = 1/2(vf²-Vo²)

The final velocity is 0

W =-1/2*20*8²

= -640J

Acceleration = -ug

= -0.200*9.8

= -1.96m/s^-2

We are to get t

t = 8/1.96

= 4.1s

P = w/t

= 640/4.1

= 156 watts

156watts is the average power that is produced by friction as the rock stops.

6 0
3 years ago
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