Answer:
E = ρ ( R1²) / 2 ∈o R
Explanation:
Given data
two cylinders are parallel
distance = d
radial distance = R
d < (R2−R1)
to find out
Express answer in terms of the variables ρE, R1, R2, R3, d, R, and constants
solution
we have two parallel cylinders
so area is 2 
R × l
and we apply here gauss law that is
EA = Q(enclosed) / ∈o ......1
so first we find Q(enclosed) = ρ Volume
Q(enclosed) = ρ ( R1² × l )
so put all value in equation 1
we get
EA = Q(enclosed) / ∈o
E(2 R × l) = ρ ( R1² × l ) / ∈o
so
E = ρ ( R1²) / 2 ∈o R
Answer:both are body waves often associated with seismic waves
Explanation:
Both are body waves often associated with seismic waves as in earthquakes
So i converted everything first;
<span>7.0 C ---> 280 K </span>
<span>49 mL---> 0.049 L </span>
<span>74mL---> 0.074 L </span>
<span>THEN I tried setting it up by the combined law formula which is P1V1/T1=P2V2/T2 </span>
'Ampere' is the unit of current. That's the rate at which
electrons travel in the circuit ... the number of electrons
every second. If you wanted the actual amount or number
of electrons, you'd need to know the length of time too.
It doesn't matter whether we're talking about a parallel or
series circuit.
Answer:
i₀ = V / R_i
Explanation:
For this exercise we use Ohm's law
V = i R
i = V / R
the equivalent resistance for
= ∑ 
if all the bulbs have the same resistance, there are N bulbs
R_{eq} = R_i / N
we substitute
i = N V / Ri
where i is the total current that passes through the parallel, the current in a branch is
i₀ = i / N
i₀ = V / R_i
