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Paraphin [41]
3 years ago
15

A pulley system lifts a 500-lb. block 2.0 feet with an effort of only 50 lb. If the 50 lb. moves 30 feet, calculate the efficien

cy of the pulley system.
Physics
2 answers:
dybincka [34]3 years ago
6 0

Answer:

Efficiency of the pulley system is 66.7 %

Explanation:

It is given that,

Input force, F_{in}=500\ lb

Distance, d₁ = 2 feet

Output force, F_{out}=50\ lb    

Distance, d₂ = 30 feet

The efficiency of pulley system is defined as ratio of output work done to the input work done i.e.

\eta=\dfrac{W_{out}}{W_{in}}

\eta=\dfrac{500\times 2}{50\times 30}\times 100

\eta=66.7\%      

Hence, the efficiency of the pulley system is 66.7 %    

tatiyna3 years ago
4 0
The answer to this is 67%
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Since the displacement is completely perpendicular to the direction of the applied force, the work done on the bag is zero.

<h3>When is the Work done on an object ?</h3>

The work is done on an object when the force applied is multiply by the distance moved by the object in the direction of the force applied.

Given that a man carries a hand bag by hanging on his hand moves horizontally where the bag does not up or down.

What is work if the displacement is not in the direction of force ?

The work done can only be zero if the displacement is perpendicular to the direction of force. otherwise, it will not be equal to zero.

Also, the work done will be zero, if the displacement is zero.

In the question above, the displacement is completely perpendicular to the direction of the applied force.

Therefore, the work done on the bag is zero.

Learn more about Work Done here: brainly.com/question/8119756

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3 years ago
A crate of eggs is located on the flat bed of a pickup truck which drives around a curve on a flat road. The curve can be treate
dlinn [17]

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Explanation:

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4 0
3 years ago
1.A student is pushing a 30 kg
Kobotan [32]

Answer:

A student is pushing a = 35 kg desk across a floor at a constant speed of 1 = 4 m/s. How

much work, to the nearest whole joule, must the student do on the desk to change the speed to

2 = 6 m/s?

Solution:

Work done = change of energy

=

2

2

2

−

1

2

2

=

35 × 36

2

−

35 × 16

2

= 630 − 280 = 350 J

Answer = 350 J

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