Answer: 3750 m
Explanation:
1) You can find in the literature or internet that the speed of sound in the ocean is about 1500 m/s.
2) Then, you can find the distance travel by the sound wave in 5.0s with the equation distance = speed × time
⇒ distance = 1500m/s × 5.0 s = 7500 m
3) That sound went down until the ocean floor below and cameback all the way until the sailor heard it.
Then, the deep of the ocean fllor is half that distance:
deep = 7500m / 2 = 3750m
Answer:
0.71ohms
Explanation:
AC and CB are in series hence the total resistance is 3+2=5ohms
AD and DB are in series hence the total resistance is 3+2=5ohms
These resistances are parallel to resistance AB
Let the equivalent resistance be R.
For resistances in parallel
Hence the total resistances are:
5//1//5
1/R =1/5 + 1/1 +1/5 = 1+5+1 /5 = 7/5
Hence the total resistance is R= 1/ 7/5 = 1×5/7= 5/7=0.71ohms
When you increase the frequency of the waves (assuming amplitude is held constant), the energy of the waves will increase, while wavelength will decrease.. Increase the frequency the light goes toward violet, decrease it and it goes toward red.
Answer: 1.04N
Explanation:
Given
q1 = 2*10^-6C
q2 = 3.6*10^-6C
r = 0.25m
k = 9*10^9
Magnitude of electrostatic force can be calculated by using coulomb's law. Coulomb's law states that, "the magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them."
F =(kq1q2) / r²
F = (9*10^9 * 2*10^-6 * 3.6*10^-6) / 0.25²
F = 0.0648/0.0625
F = 1.04N
The type of electrostatic force between the charges is the repulsive force