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UkoKoshka [18]
3 years ago
10

Can you please help me I’ll give you a brainlist an it’s science

Biology
2 answers:
Nostrana [21]3 years ago
6 0

Answer:

C.

Explanation:

Electron are in the motion around a nucleus that contains protons and neutrons.

Remember:

Electron are in outer of nucleus

Airida [17]3 years ago
6 0

Answer:

option c is correct

Explanation:

electron are in motion around the nucleus(in orbit) which contain neutron and proton

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Which coast of north America has the greater amount of earthquakes, volcanoes and mountain s?
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How does nitrogen leave a food chain?
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In 1985 a biologist counted 750 pine trees in a 250 hectare forest. Using similar counting techniques, the biologist counted 1,2
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Suppose that we have a given function f(x)

The average rate of change of the function between two values x₁ and x₂ is given by:

r = \frac{f(x_2) - f(x_1)}{x_2 - x_1}

a) We want to find the average (rate) of change on the size of population from 1985 to 1995.

We have that:

f(1985) = 750

f(1995) = 1500

Then we have:

r = \frac{1500 - 750}{1995 - 1985}  = 750/10 = 75

This means that the population of trees increases, in average, at a rate of 75 trees per year.

b) What is the density of trees each year that they were counted?

This will be equal to the quotient between the number of trees and the area.

1985: number of trees = 750 pines

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Then the density is:

D(1985) = (750 pines)/(250 ha) = 3 pines/ha

So 1985, there were 3 pines per hectare.

1990: number of trees = 1250 pines

         area = 250 ha

Then the density is:

D(1990) = (1250 pines)/(250 ha) = 5 pines/ha

1995: number of trees = 1500 pines

         area = 250 ha

The density is:

D(1995) = (1500 pines)/(250 ha) = 6 pines/ha

3) now we want to get the average change between 1985 and 1995 in the density, this will be:

r = \frac{D(1995) - D(1885)}{1995 - 1985}  = \frac{6 pines/ha - 3pines/ha}{10}  = 0.3 pines/ha

So, on average, each year the number of pines per hectare increases by 0.3

7 0
3 years ago
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