M=log I / S
if M=6, 6=logI/S and then 10^6=I/S, so we get I=S <span>x 10^6, we assume that
</span>A=S x 10^6
if M=8, so, 8=logI/S and then 10^8=I/S, so we get I= S x 10^8=A=S x 10^6x10^2
since A=S x 10^6, so I= <span>A x10^2, </span><span>an earthquake with a magnitude of 8 is 10² stronger than an earthquake with a magnitude of 6.</span>
<span>two divided by the difference of a number and 3 minus 4 divided by a number plus 3, equals 8 times the reciprocal of the difference of the number squared and 9.
let x=number
2/(x-3)-4/(x+3)=8/(x^2-9)=8/(x+3)(x-3)
LCD: (x+3)(x-3)
2(x+3)-4(x-3)=8
2x+6-4x+12=8
-2x+18=8
-2x=-10
x=5</span>
Since we're given y, we can substitute y into the first euqation...
-2x+3(3x+4)=19
-2x+9x+12=19
7x=7
x=1
hope this helps :D brainliest pls
