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3 years ago

5

Can somebody help me I’m stuck with this!!

1 answer:

Mama L [17]3 years ago

3 0

I believe it’s A, C, and E

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In the parallelogram shown, find x in terms of u and v.

Lubov Fominskaja [6]

Answer:

x = 2u -v

Step-by-step explanation:

X is the excess when we try to squeeze 2 u's on the side v,therefore

x = 2u -v

4 0

3 years ago

PLEASE HELP ME ASAP!!!

rjkz [21]

Answer:

d) $7^{14}$

Step-by-step explanation:

we simplify $(7^{7})^{2}$ by doing 7 x 2 = 14

so it is now

$7^{14}$

to check, we can use a calculator.

7 to the power of 14 = 678223072849

and

7 to the power of 7, squared also = 678223072849

Hope this helps!

7 0

2 years ago

Help please!! Just need C <br><br>(don't worry about the background shapes)

horrorfan [7]

I think not fpr sure though

8 0

3 years ago

Determine the range of the function. (0,2) (2,4) (4,6) (6,8) (8,10)

stealth61 [152]

The answer might be f(x)≥2

7 0

3 years ago

Read 2 more answers

How many solutions does the equation x_1 +x_2+x_3+x_4+x_5=21 have where x_1, x_2, x_3, x_4, and x_5 are nonnegative integers and

omeli [17]

Step-by-step explanation:

$x_{1} + x_{2} + x_{3} + x_{4} + x_{5} = 21\\$ (given)

Let us consider :

$x_{1}$ = $t_{1} + 1$

$x_{2}$ = $t_{2}$

$x_{3}$ = $t_{3}$

$x_{4}$ = $t_{4}$

$x_{5}$ = $t_{5}$

Now, by substituting the above considerations in the above equation, we get:

$t_{1} + 1 + t_{2} + t_{3} + t_{4} + t_{5} = 21\\$

$t_{1} + t_{2} + t_{3} + t_{4} + t_{5} = 20\\$

where,

$t_{i}$ $\geq$ 1

then it follows

n = 20

r = 4

then no. of solutions for the eqn = $_{r}^{n + r}\textrm{C}$

= $_{4}^{24}\textrm{C}$

= 10626

Answer :

no. of solutions for the eqn 10626

4 0

3 years ago