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Temka [501]
3 years ago
6

Consider the line =+3x6y−8 . what is the slope of a line parallel to this line? what is the slope of a line perpendicular to thi

s line?
Mathematics
1 answer:
Reil [10]3 years ago
7 0
<span>Two lines are parallel if their slope is the same.
You want to write 8x + 4y = 5 in the form y = mx + b, where m represents the slope and b is the y-intercept.
We need to isolate y in the given equation. The number next to x is the slope.
8x + 4y = 5
4y = -8x + 5

y = (-8x +5)/4
y = -2x + 5/4
The slope of the line we want is -2.
Two lines are perpendicular if the slope of the first line times the slope of the second line produces a product of negative one.
Since our slope is -2, we know that -2 times 1/2 yields -1.
The slope of the line perpendicular is 1/2. </span>
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4 years ago
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Note: Im guessing you're here for rsm struggles. That's how I found this question. I searched the web for the answer to this rsm problem, but I couldnt find it. I was happy to find this brainly link, but annoyed to find it was unanswered. I did the problem, and now i'll help future rsm strugglers out. Thanks for posting this question.

Step-by-step explanation:

Ok, so we know that trinomials like this are squares of binomials. this in mind, we know that it can also be written as (x+y)^2. (also brainly's exponents feature used to be better, if the exponents are confusing you, comment.) Using the (x+y)^2 equation, you know that by simplifying it, you get x^2+2xy+y^2. Basically we're looking for x^2. Using the middle term, 2xy, or 12x in this equation, we can find x. since we know the square root of 1 is 1, we know 12=2x. This is kinda confusing, but basically since the answer is 6, we know that the x-term is 6x. We square 6x and get 36x^2. guaranteed to work on the rsm student portal, i'm in rsm and i just answered this question.

Hope this helps! Also, im not usually too active on brainly unless im looking for HW answers, so if you understand this explanation and you see a confused comment, help out a friend and answer it. Happy holidays!

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