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3 years ago

Please help me answer this question.

Mathematics

1 answer:

charle [14.2K]3 years ago

4 0

$\bf \textit{hmm how much is 0.25 of the pizzas?}\quad 0.25\cdot 40\implies \boxed{10}\leftarrow Ronnie
\\\\\\
\textit{we know Mack stacked only \boxed{9}}
\\\\\\
\textit{what is the 35\% of 40?}\quad \left(\frac{35}{100} \right)\cdot 40\implies \boxed{14}\leftarrow Kim
\\\\\\
\textit{how many remain?}\quad 40-(10+9+14)\implies \boxed{7}\leftarrow Ada$

so.. that's how many each did, surely you'd know who did the most pizzas.

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Step-by-step explanation:

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2 years ago

A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time).

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Answer:

(a). 72.9%.

(b). 13.6 hr.

Step-by-step explanation:

So, we are given the following data or parameters or information which is going to assist us in solving this question/problem;

=> "A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). "

=> The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes"

So, we will be making use of the Crawford learning curve model.

T(7) + 10 = T (17) = 30 min.

T(7) = T1(7)^b = 45.

T(17 ) = T1(17)^b = 30.

(T1) = 45/7^b = 30/17^b.

45/30 = 7^b/17^b = (7/17)^b.

1.5 = (0.41177)^b.

ln 1.5 = b ln 0.41177.

0.40547 = -0.8873 b.

b = - 0.45696.

=> 2^ -0.45696 = 0.7285.

= 72.9%.

(b). T1= 45/7^ - 045696 = 109.5 hr.

V(TT)(17) = 109.5 {(17.51^ - 0.45696 – 0.51^ - 0.45696) / (1 - 0.45696)} .

V(TT) (17) = 109.5 {(4.7317 - 0.6863) / 0.54304} .

= 815.7 min .

= 13.595 hr.

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Answer:

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Step-by-step explanation:

Price without Discount Card Price with Discount Card

Ticket (12 & Under) $10 $8

Adult's Ticket $15 $12

Let x be the number of visits

Price without discount card for 2 adults and 1 child ticket

Price without discount for x visits = $x(15 \times 2+ 10)=40x$

Price with discount for x visits = $57+ x(12 \times 2+ 8)=57+32x$

Now to find For what number of visits will the total cost of the visits (including the price of the discount card) be less expensive for a family of 2 adults and 1 child if they have purchased the discount card

57+32x< 40x

57<8x

7.1<x

So, 8 number of visits will be the total cost of the visits (including the price of the discount card) be less expensive for a family of 2 adults and 1 child if they have purchased the discount card

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