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rusak2 [61]
3 years ago
12

ANSWER PLS!! HELP! WILL GIVE BRAINLIEST

Mathematics
2 answers:
NeTakaya3 years ago
5 0

For this case we have that the temperature drops steadily at a speed of {\sf0.8\:\frac{degree}{hours}}, that is, every hour drops 0.8 degrees. So, we can propose a rule of three:

1 hour ----------> 0.8 degrees

x ------------------> 4.4 degrees

Where the variable "x" represents the number of hours that must pass for the temperature to decrease by 4.4 degrees.

{\sf{x\:=\:\frac{4.4\:x\:1}{0.8}

{\sf{x\:=\:5.5

Thus, for the temperature to decrease by 4.4 degrees, 5.5 hours must pass.

<u>Answer:</u>

5.5 hours

malfutka [58]3 years ago
4 0

Answer:

5.5 hrs

Step-by-step explanation:

1 hr --> -0.8 hrs

? --> -4.4°C

-4.4 / -0.8 = 5.5 hrs

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Answer:

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Step-by-step explanation:

The equation of direct variation is ...

  y = kx

for some constant k. Here, we have x in hours and y in dollars. We can see if k is constant for the values given in the table.

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<h3>constant of variation</h3>

Solving the direct variation formula for k, we have ...

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Using the table values, we can see if this is constant:

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answer
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NeX [460]

Answer:

The function is y~=~12 ~-~ 0.5 \cdot x.

The slope is m=-0.5.

The y-intercept is b=12.

Step-by-step explanation:

Our aim is to calculate the values <em>m</em> (slope) and <em>b</em> (y-intercept) in the equation of a line :

y=mx+b

We have the following data:

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To find the line of best fit for the points given, you must:

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Step 2: Find the sum of every column:

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Step 3: Use the following equations to find <em>b</em> and <em>m</em>:

\begin{aligned}        b &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} =             \frac{ 36 \cdot 200 - 24 \cdot 188}{ 4 \cdot 200 - 24^2} \approx 12 \\ \\m &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2}        = \frac{ 4 \cdot 188 - 24 \cdot 36 }{ 4 \cdot 200 - \left( 24 \right)^2} \approx -0.5\end{aligned}

Step 4: Assemble the equation of a line

\begin{aligned} y~&=~b ~+~ m \cdot x \\y~&=~12 ~-~ 0.5 \cdot x\end{aligned}

The graph of the regression line is:

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