To find the y-intercept: replace x with 0
to find the x-intercept: replace y with 0
x-int:
0 = 10x - 32
32 = 10x
x = 3.2
(3.2, 0)
y-int:
y = 10(0) - 32
y = -32
(0, -32)
The derivative of 1/logx is With the chain rule.
1log(x)=log(x)−1 is ,= -1xlog(x)2 .
The by-product of logₐ x (log x with base a) is 1/(x ln a). Here, the thrilling issue is that we have "ln" withinside the by-product of "log x". Note that "ln" is referred to as the logarithm (or) it's miles a logarithm with base "e".
The by-product of 1/log x is -1/x(log x)^2. Note that 1/logx is the reciprocal of log.

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1. H+S=40
2. 19H+25S=922
From 1,
19H+19S=760
Subtract this from 2 to eliminate H,
19H+25S-19H-19S=922-760
6S=162
Solve for S, then use either equation to solve for H.
24/4.7=x x=5.1
24+x=what you want
24+5.1=29.1 there you go
Answer:
Step-by-step explanation:
2(13x – 7). 11.