Answer:
No real zeros.
Step-by-step explanation:
![\boxed{\begin{minipage}{7.4 cm}\underline{Discriminant of the Quadratic Formula}\\\\$b^2-4ac$ \quad when $ax^2+bx+c=0$\\\\When $b^2-4ac > 0 \implies$ two real zeros.\\When $b^2-4ac=0 \implies$ one real zero.\\When $b^2-4ac < 0 \implies$ no real zeros.\\\end{minipage}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cbegin%7Bminipage%7D%7B7.4%20cm%7D%5Cunderline%7BDiscriminant%20of%20the%20Quadratic%20Formula%7D%5C%5C%5C%5C%24b%5E2-4ac%24%20%5Cquad%20when%20%24ax%5E2%2Bbx%2Bc%3D0%24%5C%5C%5C%5CWhen%20%24b%5E2-4ac%20%3E%200%20%5Cimplies%24%20two%20real%20zeros.%5C%5CWhen%20%24b%5E2-4ac%3D0%20%5Cimplies%24%20one%20real%20zero.%5C%5CWhen%20%24b%5E2-4ac%20%3C%200%20%5Cimplies%24%20no%20real%20zeros.%5C%5C%5Cend%7Bminipage%7D%7D)
The value of the discriminant shows how many zeros the function has.
<u>Given quadratic function</u>:
![f(x)=5x^2+5x+21](https://tex.z-dn.net/?f=f%28x%29%3D5x%5E2%2B5x%2B21)
Therefore:
Substitute the values into the discriminant and solve:
![\begin{aligned}\implies b^2-4ac&=(5)^2-4(5)(21)\\& = 25 - 20(21)\\&=25-420\\&=-395\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5Cimplies%20b%5E2-4ac%26%3D%285%29%5E2-4%285%29%2821%29%5C%5C%26%20%3D%2025%20-%2020%2821%29%5C%5C%26%3D25-420%5C%5C%26%3D-395%5Cend%7Baligned%7D)
Therefore, as -395 < 0, there are no real zeros.
Answer:
$387
Step-by-step explanation:
Answer:
A,B,C,D
Step-by-step explanation:
Mark the unknown number as x
Now the long side is x-3 inches
S=long side*short side=(x-3)*2=2x-6 square inches
S < 12 so
2x-6 < 12
2x < 12+6
2x<18
x<9
2<4<6<8<9
Answer:
D.) g(x) = -x² - 3
Step-by-step explanation:
The function was shifted 3 down...
x² ↓ 3 = x² - 3
and inverted, giving you this:
-1 · x² - 3 = -x² - 3
<em>g(x) = -x² - 3</em>