Question

find three consecutive even integers such that the sum of twice the smallest and three times the largest is 42

Answer 1

$2n,2n+2,2n+4\\\\\\2\cdot2n+3(2n+4)=42\\\\4n+6n+12=42\\\\10n=30\\\\n=3\\\\2n=2\cdot3=6\\2n+2=6+2=8\\2n+4=6+4=10$

6,8,10