If the legs are length a and b and hyptonuse is c then
a²+b²=c²
so
if the legs are 20 and 21 and the hypotnuse is x then
20²+21²=x²
400+441=x²
841=x²
29=x
The answer is 2-7x I'm 100% sure
So, the shortest side is 13, the other two fellows are two consecutive values.... ok... let's say the other leg is "a", a consecutive value to that will be a+1, so the hypotenuse is "a + 1" then
check the picture below
and surely you'd know what "a" is
6.5 lbs/100lbs but what is it out of? 6.5 lbs out of what? 6.5/10 6.5/10000000lbs???