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3 years ago

6 sheep or 8 cows can graze a field in 34 days. How long would 9 sheep and 5 cows take to graze the same field?

Mathematics

2 answers:

Ludmilka [50]3 years ago

7 0

Answer:

16 days would be taken.

Step-by-step explanation:

Given that:

6 sheep = 8 cows

1 sheep = (8/6) cows

9 sheep = (8*9)/6 cows

9 sheep = 12 cows

9 sheep + 5 cows = 12 cows + 5 cows

= 17 cows

Now 8 cows can gaze field in 34 days

1 cow can gaze field in (34 * 8) days

17 cows can gaze field in (34*8)/17 days = 16 days

So 9 sheep and 5 cows will take 16 days to graze the field.

Zarrin [17]3 years ago

3 0

Answer:

16 days would be how long it would take

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$\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k$

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