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Nana76 [90]
3 years ago
14

The New Horizons probe flew past Pluto in July 2015. At the time, Pluto was about 32 AU from Earth. How long did it take for com

munication from the probe to reach Earth, given that the speed of light in km/hr is 1.08 × 109?
Physics
1 answer:
UkoKoshka [18]3 years ago
4 0

Answer:

15944.6 sec

Explanation:

d = distance of Pluto from earth = 32 AU = 32 x 1.496 x 10¹¹ m

v = speed of light = 1.08 x 10⁹ km/hr = ( 1.08 x 10⁹) (0.278) m/s

t = time taken for the communication to reach from probe to earth = ?

Using the equation

d = v t

Inserting the values given

32 x 1.496 x 10¹¹ = (( 1.08 x 10⁹) (0.278)) t

t = 15944.6 sec

t = 1.6 x 10⁴ sec

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Which term, when divided by volume, equals density?
vredina [299]

Answer:

C) Mass

Explanation:

The mass of an object divided by its volume equals the density.

Hope this helps!

8 0
3 years ago
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A 69 kg zebra is traveling 7 m/s east. What is the zebra’s momentum? kg-m/s
Hitman42 [59]
Linear momentum is the product of mass and velocity. In this case, it is simply:
69\times 7 = 483 kg\cdot m/s
6 0
3 years ago
I do not know where to start.
irakobra [83]
Underline the words then eliminate the ones that arent part of the problem!
4 0
3 years ago
"My distance to the center of the earth is about 4000 miles when I am on the surface. If I go to a height of 8000 miles above th
lord [1]

Given,

Distance from the surface to the center of the earth, d=4000 miles

Distance from the center to you at a height of 8000 miles, a= 8000+4000=12000 miles

The gravitational force acting on a person at the surface is equal to his weight.

From Newton's Universal Law of Gravitation, the gravitational force is

F=\frac{G\times M\times m}{r^2}

Where G is the gravitational constant, M is the mass of the earth, m is the mass of the object/person, r is the distance between the center of the earth and the object/person

At the surface, this force is equal to the weight of the person, W=mg

i.e.

F_s=\frac{G\times M\times m}{d^2}=W

On substituting the of d,

W=\frac{\text{GMm}}{4000^2}

At a height of 8000 miles from the surface, the gravitational force is equal to,

F_a=\frac{GMm}{12000^2}

On dividing the above two equations,

\frac{F_a}{W}=\frac{4000^2^{}}{12000^2}=\frac{1}{9}

Therefore,

F_a=\frac{1}{9}W

Therefore at a height of 8000 miles above the surface of the earth, the force of gravity becomes 1/9 time your weight.

5 0
1 year ago
Find the net force and acceleration. 10 points. Will give brainliest.
Afina-wow [57]

Answer:

a) 16 N

b) 2.13 m/s²

Explanation:

Draw a free body diagram of the tv stand.  There are four forces:

Weight force mg pulling down,

Normal force N pushing up,

Friction force Nμ pushing left,

and applied force P pulling right.

Sum of forces in the y direction:

∑F = ma

N − mg = 0

N = mg

The net force in the x direction is:

∑F = P − Nμ

∑F = P − mgμ

∑F = 25 N − (7.5 kg) (10 m/s²) (0.12)

∑F = 16 N

Net force equals mass times acceleration:

∑F = ma

16 N = (7.5 kg) a

a = 2.13 m/s²

3 0
3 years ago
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