Which plate is made up almost entirely of oceanic crust

Physics

2 answers:

OLga [1]3 years ago

7 0

Answer:

Explanation:

i got it right

nordsb [41]3 years ago

6 0

Answer:

D. Pacific Plate

Explanation:

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One way to monitor global warming is to measure the average temperature of the ocean. Researchers are doing this by measuring th

Marat540 [252]

Answer:

0.07°C

Explanation:

solution:

the speed of a sound in water is:

v(T)=1480+4(T-4°C)

at 4°C the travel time is:

t(4◦C) = ( 7600 × 103 m ) / (1480 m/s) = 5202.7 s

5°C, the travel time is:

t(5◦C) = ( 7600 × 103 m ) / (1484 m/s) = 5188.7 s

one degree C corresponds to a ∆t of 14 s so temperature difference is:

ΔT=1 s/14 s=0.07◦C

5 0

3 years ago

Determine the gravitational field 300km above the surface of the earth. How does this compare to the field on the earth's surfac

Serjik [45]

The strength of the gravitational field is given by:
$g= \frac{GM}{r^2}$
where
G is the gravitational constant
M is the Earth's mass
r is the distance measured from the centre of the planet.

In our problem, we are located at 300 km above the surface. Since the Earth radius is R=6370 km, the distance from the Earth's center is:
$r=R+h=6370 km+300 km=6670 km= 6.67 \cdot 10^{6} m$

And now we can use the previous equation to calculate the field strength at that altitude:
$g= \frac{GM}{r^2}= \frac{(6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2})(5.97 \cdot 10^{24} kg)}{(6.67 \cdot 10^6 m)^2} = 8.95 m/s^2$

And we can see this value is a bit less than the gravitational strength at the surface, which is $g_s = 9.81 m/s^2$ .