I need help please help me

Circle X with a radius of 6 units and circle Y with a

Minchanka [31]

Answer:

The answer is C, Translate the circles so they share a common center point, and dilate circle Y by a scale factor of 3.

Step-by-step explanation:

8 0

2 years ago

5. Write 895,003,049 in expanded form.

aleksandr82 [10.1K]

Answer:

800,000,000 90,000,000 5,000,000 3,000 40 9

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

I need help, it’s a true or false question

marusya05 [52]

Answer:

The answer to this is False, False, True.

Step-by-step explanation:

A is false because WAU is an obstute angle, which can't be 55 degree.

B is flase because YAU is actually the angle that is 55 degree, not 35 degree.

C is true because WAX is congruent to YAU and it is 55 degree.

5 0

2 years ago

Please answer the two questions!

shutvik [7]

Given:

The expressions are

(c) $\left\{\left(\dfrac{2^4\times 3^6}{12^2}\right)^0\right\}^3$

(d) $\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}$

To find:

The simplified form of the given expression.

Solution:

(c)

We have,

$\left\{\left(\dfrac{2^4\times 3^6}{12^2}\right)^0\right\}^3$

We know that, zero to the power of a non-zero number is always 1. So, $\left(\dfrac{2^4\times 3^6}{12^2}\right)^0=1$

$\left\{\left(\dfrac{2^4\times 3^6}{12^2}\right)^0\right\}^3=(1)^3$

$\left\{\left(\dfrac{2^4\times 3^6}{12^2}\right)^0\right\}^3=1$

Therefore, the value of the given expression is 1.

(d)

We have,

$\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}$

It can be written as

$\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}=\dfrac{13^3\times 1}{(65\times 49)^2}$

$\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}=\dfrac{13\times 13\times 13}{(65\times 49)(65\times 49)}$

$\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}=\dfrac{13}{(5\times 49)(5\times 49)}$

$\dfrac{13^3\times 7^0}{\{(65\times 49)^2\}^1}=\dfrac{13}{60025}$

Therefore, the value of given expression is $\dfrac{13}{60025}$ .

7 0

2 years ago

I dunno, need help!

kodGreya [7K]

It is d,c,b im pretty sure

7 0

3 years ago