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jeyben [28]
3 years ago
14

How do I solve this and what’s the answer?

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
6 0

Answer:

Mike can go 124 miles

Step-by-step explanation:

Car rent = $29.20

However, a customer has to pay $0.20 for every mile.

Mike has $54 to spend on the car for a day.

If he pays the car rent which is $29.20, then he has

$54 - $29.20 = $24.80 remaining

1 mile = $0.20

x miles = $24.80

By cross multiplication

0.20x = 1 * 24.80

x = 24.80/0.20

x = 124 miles

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Write yhr equation in standard form of the line with m=3/4 and b=6
ozzi

Answer:

y = 3/4 x + 6

Step-by-step explanation:

y = mx + b

y = 3/4 x + 6

3 0
3 years ago
6. The dimensions of a rectangular garden are 380ft x 250ft. If you want to walk around this garden to make 3 miles for a mornin
SSSSS [86.1K]

Answer:

Step-by-step explanation:

L=3(5280)/(2(380+250))

L=15840/1260

L=12.57

So to walk three miles one must walk around the garden 12.57 times.

7 0
2 years ago
Are 4/16 and 0.25/2 equivalent numbers? If so, explain how they are.
Aleksandr-060686 [28]
Two fractions are equivalent if the product of the numerator of the first and the denominator of the second is equal to the product of the numerator of the second and the denominator of the first.
                           4 x 2 ___ 16 x 0.25
                               8 is not equal to 4
Thus, they are not equivalent. 
3 0
3 years ago
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
sleet_krkn [62]

This question is incomplete, the complete question is;

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.

In other words, how many 5-tuples of integers  ( h, i , j , m ), are there with  n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?

Answer:

the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Step-by-step explanation:

Given the data in the question;

Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1

this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.

So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'

Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;

\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right]

= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]

= [( n + 4 )!] / [ 5!( n-1 )! ]

= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

4 0
3 years ago
Beinggreat78 please answer fast
alexdok [17]
The perimeter is 48 units
6 0
2 years ago
Read 2 more answers
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