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jeyben [28]
3 years ago
14

How do I solve this and what’s the answer?

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
6 0

Answer:

Mike can go 124 miles

Step-by-step explanation:

Car rent = $29.20

However, a customer has to pay $0.20 for every mile.

Mike has $54 to spend on the car for a day.

If he pays the car rent which is $29.20, then he has

$54 - $29.20 = $24.80 remaining

1 mile = $0.20

x miles = $24.80

By cross multiplication

0.20x = 1 * 24.80

x = 24.80/0.20

x = 124 miles

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60.8 is what percent of 32
Anna71 [15]
60.8 is 190% of 32

Divide 60.8 over 32:
\frac{60.8}{32} = 1.9

Convert the decimal into a percentage by dividing it over 100:
1.9 \times 100 = 190
5 0
3 years ago
Explain how to find the pre-tax cost of an item if you know the final cost and the sales tax rate.
JulijaS [17]

Answer:

Calculating total cost.Multiply the cost of the item or service by the sales tax in order to find out the total cost.The equation looks like this:Item or service cost x sales tax (in decimal form) = total sales tax.Add the total sales tax to the item or service cost to get your total cost.

Step-by-step explanation:

#Princesses Rule

6 0
2 years ago
Translate the sentence into an equation.
earnstyle [38]

Answer:

Eight times the sum of a number and 2 is equal to 7.

times = multiply

sum = ()

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8(w + 2 ) = 7

3 0
2 years ago
Which is a simplified form of the expression -4(n + 1) – (n + 2)?
Nadya [2.5K]

Answer:

-(5 n + 6)

Step-by-step explanation:

Simplify the following:

-4 (n + 1) - (n + 2)

-4 (n + 1) = -4 n - 4:

-4 n - 4 - (n + 2)

-(n + 2) = -n - 2:

-4 - 4 n + -n - 2

Grouping like terms, -4 - 4 n - 2 - n = (-4 n - n) + (-4 - 2):

(-4 n - n) + (-4 - 2)

-4 n - n = -5 n:

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-4 - 2 = -(4 + 2):

-5 n + -(4 + 2)

4 + 2 = 6:

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Factor -1 out of -5 n - 6:

Answer: -(5 n + 6)

4 0
3 years ago
Read 2 more answers
Determine whether the series is convergent or divergent by expressing sn as a telescoping sum (as in Example 8). [infinity] 6 n2
vekshin1

Answer:

Step-by-step explanation:

given

\sum\limits^\infty_{n=3}\frac{6}{n^2-1}=\sum\limits^\infty_{n=3}\frac{6}{(n-1)(n+1)}\\\\=\sum\limits^\infty_{n=3}\frac{6}{2}(\frac{1}{n-1}-\frac{1}{n+1})\\\\=\frac{6}{2}\sum\limits^\infty_{n=3}(\frac{1}{n-1}-\frac{1}{n+1})\\\\=3[(\frac{1}{2}-\frac{1}{4})+(\frac{1}{3}-\frac{1}{5})+(\frac{1}{4}-\frac{1}{6})+(\frac{1}{5}-\frac{1}{7})+...]\\\\=3[\frac{1}{2}+\frac{1}{3}]=3[\frac{3+2}{6}]=3[\frac{5}{6}]\\\\=\frac{15}{6}=\frac{5}{3}

5 0
3 years ago
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