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2 years ago

NEED HELP AND FAST

Mathematics

1 answer:

11111nata11111 [884]2 years ago

8 0

Answer:

it's 20 I hope it will help you please follow me

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-3x-4=-13 solve inequality plz show work!

Lady bird [3.3K]

Hello Again!

What you want to do first is add 4 to -4 and to -13. After doing so, you'll equation will look a little something like this...

-3x=9

You'll then want to divide both -3 and 9 by -3. After doing so, the equation will look like this...

x=-3

Your answer is x=-3

I hope this helps

6 0

3 years ago

Read 2 more answers

which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1

lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. $y=\sec x$

B. $y= \tan x$

C. $y= \cot x$

D. $y= \csc x$

Answer:

A. $y=\sec x$

D. $y=\csc x$

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: $y=\sec x$

We know that, the $\sec x=\frac{1}{\cos x}$

The range of $\cos x$ is from -1 to 1 given as [-1, 1]. So,

$|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the secant function as:

$\sec x\leq -1\ or\ \sec x\geq 1\\$

Therefore, the range of $y=\sec x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

Choice B: $y= \tan x$

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: $y= \cot x$

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: $y=\csc x$

We know that, the $\csc x=\frac{1}{\sin x}$

The range of $\sin x$ is from -1 to 1 given as [-1, 1]. So,

$|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

$\csc x\leq -1\ or\ \csc x\geq 1\\$

Therefore, the range of $y=\csc x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

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3 years ago

“When I left the house this morning, I noticed that I was short on cash,” Gary said. “I spent one-half of what I had on my train

nexus9112 [7]

I don't know the answer

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3 years ago

Solve the following system of equations: −2x + y = 1 −4x + y = −1

Katyanochek1 [597]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}-2x+y=1\\-4x+y=-1&\text{change the signs}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-2x+y=1\\4x-y=1\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad2x=2\qquad\text{divide both sides by 2}\\.\qquad x=1\\\\\text{Put it to the first equation:}\\\\-2(1)+y=1\\-2+y=1\qquad\text{add 2 to both sides}\\y=3$

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3 years ago

Ribbon A is 1/3 meters long. It is 2/5 meters shorter than ribbon b. What's the total length of 2 ribbons?

Pavel [41]

1/3+2/5=5/15+10/15
answer is 1

4 0

3 years ago