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Anna007 [38]
3 years ago
7

When a group 1 element and a group 16 element bond, the subscripts in the formula will always be?

Chemistry
1 answer:
zloy xaker [14]3 years ago
4 0

Answer:

A.  

X2Y2

Explanation:

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What is the only letter not appearing on the periodic table?.
ivolga24 [154]

Answer:

The answer is j

Explanation:

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3 years ago
C como Se define una cuenca hidrogatica<br><br>Ayudaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa<br><br><br><br>​
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Answer:

Una cuenca es un área de tierra que drena todos los arroyos y la lluvia a una salida común, como la salida de un embalse, la boca de una bahía o cualquier punto a lo largo del canal de un arroyo.

Explanation:

Espero que esto ayude a marcar el MÁS CEREBRAL !!!

7 0
3 years ago
What are some properties of matter that can be identified without testing or measuring
kiruha [24]
Physical change - No change of matter in this phase
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8 0
3 years ago
A solution is prepared from 4.5701 g of magnesium chloride and 43.238 g of water. The vapor pressure of water above this solutio
balandron [24]

Answer:

i = 2.483

Explanation:

The vapour pressure lowering formula is:

Pₐ = Xₐ×P⁰ₐ <em>(1)</em>

For electrolytes:

Pₐ = nH₂O / (nH₂O + inMgCl₂)×P⁰ₐ

Where:

Pₐ is vapor pressure of solution (<em>0.3624atm</em>), nH₂O are moles of water, nMgCl₂ are moles of MgCl₂, i is Van't Hoff Factor, Xₐ is mole fraction of solvent and P⁰ₐ is pressure of pure solvent (<em>0.3804atm</em>)

4.5701g of MgCl₂ are:

4.5701g ₓ (1mol / 95.211g) = 0.048000 moles

43.238g of water are:

43.238g ₓ (1mol / 18.015g) = 2.400 moles

Replacing in (1):

0.3624atm = 2,4mol / (2.4mol + i*0.048mol)×0.3804atm

0.3624atm / 0.3804atm = 2,4mol / (2.4mol + i*0.048mol)

2.4mol + i*0.048mol = 2.4mol / 0.9527

2.4mol + i*0.048mol = 2.5192mol

i*0.048mol = 2.5192mol - 2.4mol

i = 0.1192mol / 0.048mol

<em>i = 2.483</em>

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I hope it helps!

4 0
3 years ago
During oxidation, which of the following is true? A. Electrons are gained, so the oxidation number increases. B. Electrons are g
EastWind [94]

Oxidation is when the overall charge (or oxidation number) increases.  The only way to increase an oxidation number is to lose an electron, thereby making the negative charges less.  The correct answer is C.

6 0
3 years ago
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