Answer:
54.4 mol
Explanation:
the equation for complete combustion of butane is
2C₄H₁₀ + 13O₂ ---> 8CO₂ + 10H₂O
molar ratio of butane to CO₂ is 2:8
this means that for every 2 mol of butane that reacts with excess oxygen, 8 mol of CO₂ is produced
when 2 mol of C₄H₁₀ reacts - 8 mol of CO₂ is produced
therefore when 13.6 mol of C₄H₁₀ reacts - 8/2 x 13.6 mol = 54.4 mol of CO₂ is produced
therefore 54.4 mol of CO₂ is produced
Answer:
Simply put, you can go from moles to grams and vice versa by using the mass of 1 mole of that substance, i.e its molar mass. For example, the molar mass of carbon is 12.011 g/mol. This means that 1 mole of carbon, or 6.022⋅1023 atoms of carbon, weigh 12.011 g.
Explanation:
Answer:
See explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem
Answer:
Requirements for a correctly written chemical equation are reactants and products, their formula and valency
Explanation:
Formula of the given compound are -
1 - Potassium Hydroxide - 
2 - Calcium Nitrate - 
The requirements for a correctly written chemical equation are -
- Identifying reactants and products
- Formula of reactants and products
- Valency of elements
Example of word equation, formula equation, and chemical equation is as follows -
Aluminium + iron9(III)oxide ⇒ aluminium oxide + iron (word equation)
+
⇒
+
(formula equation)
+
⇒
+
(chemical equation)
Answer:
Explanation:
A. Attached is a page which contain the structural formula of the three compounds of C3H80.
Condensed structural formula of C3H8O:
Propan-1-ol: CH3CH2CH2OH
Propan-2-ol: CH3CH(OH)CH3
Methoxy methane: CH3OCH2CH3
B. Attached are is a page which contain the structural formula of the three compounds of C3H60.
Condensed structural formula of C3H6O:
Propanal: CH3CH2CHO
Propanone: CH3COCH3
Cyclopropanol: (C3H5)OH
2-propen-1-ol: CH2CHCH2OH
1-propenol: CH3CHCHOH