1 mole of any gas is equivalent to?

A helium balloon contains 16.9 L of helium at STP. How many atoms of helium are in the balloon

Zepler [3.9K]

4.54×10^(23) atoms He

8 0

3 years ago

Which particle is a neutron most equal to in mass? A. a molecule B. an atom C. a proton D. an electron

olchik [2.2K]

Answer:

c . a proton

Protons and neutrons have approximately the same mass, about 1.67 × 10−24 grams

5 0

3 years ago

Use the periodic table to answer the questions below.

madreJ [45]

The diagram that show the correct electron configuration is the second option. ⬆⬇1s, ⬆⬇2s, ⬆⬆⬆2p.

<h3>What is electronic configuration?</h3>

The electronic configuration is the representation of electron present indifferent energy levels is an atom. The different type of orbitals are s, p, d, and f.

Thus, the correct option is 2, ⬆⬇1s, ⬆⬇2s, ⬆⬆⬆2p.

Learn more about electronic configuration

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5 0

2 years ago

What is the molarity of an aqueous solution that contains 78g of C6H12O6 dissolved in 2500 mL of solution?

dusya [7]

Answer:

$\boxed {\boxed {\sf molarity = 0.17 \ M \ C_6H_12O_6}}$

Explanation:

Molarity is found by dividing the moles of solute by liters of solution.

$molarity = \frac {moles}{liters}$

We are given grams of a compound and milliliters of solution, so we must make 2 conversions.

1. Gram to Moles

We must use the molar mass. First, use the Periodic Table to find the molar masses of the individual elements.

C: 12.011 g/mol
H: 1.008 g/mol
O: 15.999 g/mol

Next, look at the formula and note the subscripts. This tells us the number of atoms in 1 molecule. We multiply the molar mass of each element by its subscript.

6(12.011)+12(1.008)+6(15.999)=180.156 g/mol

Use this number as a ratio.

$\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}$

Multiply by the given number of grams.

$78 \ g \ C_6H_12O_6 *\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}$

Flip the fraction and divide.

$78 \ g \ C_6H_12O_6 *\frac { 1 \ mol \ C_6H_12O_6}{180.156 \ g\ C_6H_12 O_6}$

$\frac { 78 \ mol \ C_6H_12O_6}{180.156 }= 0.432958102977 \ mol \ C_6H_12O_6$

2. Milliliters to Liters

There are 1000 milliliters in 1 liter.

$\frac {1 \ L }{ 1000 \ mL}$

Multiply by 2500 mL.

$2500 \ mL* \frac {1 \ L }{ 1000 \ mL}$

$2500 * \frac {1 \ L }{ 1000 }= 2.5 \ L$

3. Calculate Molarity

Finally, divide the moles by the liters.

$molarity = \frac {0.432958102977 \ mol \ C_6H_12O_6}{ 2.5 \ L}$

$molarity = 0.173183241191 \ mol \ C_6H_12O_6/L$

The original measurement has 2 significant figures, so our answer must have the same. That is the hundredth place and the 3 tells us to leave the 7.

$molarity \approx 0.17 \ mol \ C_6H_12O_6 /L$

1 mole per liter is also equal to 1 M.

$molarity = 0.17 \ M \ C_6H_12O_6$

3 0

3 years ago

If solutions of nh4cl(aq) and nh3(aq) are mixed, which ions in the resulting solution are spectator ions in any acid-base chemis

Gwar [14]

If solutions of nh4cl(aq) and nh3(aq) are mixed, the ions in the resulting solution that would be the spectator ions in any acid-base chemistry occurring in the solution would be the chloride ions. The mixture is a common buffer of ammonia and ammonium chloride. NH4Cl is a salt that is soluble in water dissociating into NH4+ and Cl-. The chloride ions are the spectator ions while NH4+ ions would be the conjugate acid for the buffer solution. Buffer solutions are solution which would resist change in pH when acid or a base is being added to the solution. The equilibrium reaction of the buffer solution in this problem would be

NH3 + H2O = OH– + NH4+

3 0

3 years ago

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