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2 years ago

Which of the following is an oxidation-reduction reaction?

Chemistry

1 answer:

garik1379 [7]2 years ago

6 0

Answer:

D) Ba(s) + 2 HCl(aq) → BaCl2(aq) + H2(g)

Explanation:

In a redox reaction, One atom is gaining electrons (Reduction) whereas other is loosing electrons (Oxidation). In the reactions:

A) HBr(aq) + NaOH(aq) → NaBr(aq) + H2O(l)

As sodium is always +1 and Br always -1, <em>this is not a redox reaction.</em>

B) NaI(aq) + AgNO3(aq) → AgI(s) + NaNO3(aq)

Sodium is always +1 and nitrate ion is -1. <em>This is not a redox reaction</em>

C) Pb(C2H3O2)2(aq) + 2 LiBr(aq) → PbBr2(s) + 2 LiC2H3O2(aq)

Acetate ion, C2H3O2 is -1 as Br is -1, lithium is +1 and Pb +2, <em>This is not a redox reactoin</em>

Barium is 0 as Ba(s) but +1 as BaCl2. Is oxidizing

Hydrogen is +1 as HCl but 0 as H2. Is reducting.

This reaction is an oxidation-reduction reaction

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Do ionic compounds or covalent compounds conduct electricity

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3 years ago

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Answer: 25.8 g of $Cl_2$ will be produced from the decomposition of 73.4 g of $AuCl_3$

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} AuCl_3=\frac{73.4g}{303g/mol}=0.242moles$

The balanced chemical reaction is:

$2AuCl_3\rightarrow 2Au+3Cl_2$

According to stoichiometry :

2 moles of $AuCl_3$ produce = 3 moles of $Cl_2$

Thus 0.242 moles of will produce= $\frac{3}{2}\times 0.242=0.363mol$ of $Cl_2$

Mass of $Cl_2$ = $moles\times {\text {Molar mass}}=0.363mol\times 71g/mol=25.8g$

Thus 25.8 g of $Cl_2$ will be produced from the decomposition of 73.4 g of $AuCl_3$

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How many moles of H2O will be produced from 26.0 g of H2022<br> Stoichiome

lukranit [14]

Answer:

0.7644 moles of H₂O

Explanation:

The balance chemical equation is as follow;

2 H₂O₂ → 2 H₂O + O₂

To solve this problem we will first calculate the moles of H₂O₂ as,

Moles = Mass / M/Mass

Moles = 26.0 g / 34.01 g/mol

Moles = 0.7644 mol

Secondly,

According to equation,

2 moles of H₂O₂ produces = 2 moles of H₂O

Hence,

0.7644 mol of H₂O₂ will produce = X moles of H₂O

Solving for X,

X = 2 mol × 0.7644 mol / 2 mol

X = 0.7644 moles of H₂O

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3 years ago