Answer:
D) Ba(s) + 2 HCl(aq) → BaCl2(aq) + H2(g)
Explanation:
In a redox reaction, One atom is gaining electrons (Reduction) whereas other is loosing electrons (Oxidation). In the reactions:
A) HBr(aq) + NaOH(aq) → NaBr(aq) + H2O(l)
As sodium is always +1 and Br always -1, <em>this is not a redox reaction.</em>
B) NaI(aq) + AgNO3(aq) → AgI(s) + NaNO3(aq)
Sodium is always +1 and nitrate ion is -1. <em>This is not a redox reaction</em>
C) Pb(C2H3O2)2(aq) + 2 LiBr(aq) → PbBr2(s) + 2 LiC2H3O2(aq)
Acetate ion, C2H3O2 is -1 as Br is -1, lithium is +1 and Pb +2, <em>This is not a redox reactoin</em>
<h3>D) Ba(s) + 2 HCl(aq) → BaCl2(aq) + H2(g)</h3>
Barium is 0 as Ba(s) but +1 as BaCl2. Is oxidizing
Hydrogen is +1 as HCl but 0 as H2. Is reducting.
This reaction is an oxidation-reduction reaction
