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2 years ago

How much water must be added to 6.0 M silver nitrate in order to make 500 mL of 1.2 M solution?

Chemistry

1 answer:

algol [13]2 years ago

7 0

The amount of water that must be added to 6.0 M silver nitrate to make 500mL of 1.2 M solution is : 2000 mL

<u>Given data :</u>

Concentration of siilver nitrate ( M₁ ) = 6.0 M

volume of solution ( V₁ ) = 500 mL

Conc of solution ( M₂ )= 1.2 M

<h3>Determine the amount of water that must be added</h3>

we will apply the equation below

M₁V₁ = M₂V₂ ---- ( 1 )

where : V₂ = V₁ + water added ---- ( 2 )

V₂ ( Final volume ) = ( M₁V₁ ) / M₂

= ( 6 * 500 ) / 1.2

= 2500 mL

Back to eqaution ( 2 )

2500 mL = 500 mL + added water

therefore ; added water = 2500 - 500

= 2000 mL

Hence we can conclude that The amount of water that must be added to 6.0 M silver nitrate to make 500mL of 1.2 M solution is : 2000 mL.

Learn more about Volume : brainly.com/question/12410983

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