Question

How much water must be added to 6.0 M silver nitrate in order to make 500 mL of 1.2 M solution?

Answer 1

The amount of water that must be added to 6.0 M silver nitrate to make 500mL of 1.2 M solution is : 2000 mL

Given data :

Concentration of siilver nitrate ( M₁ ) = 6.0 M

volume of solution ( V₁ ) = 500 mL

Conc of solution ( M₂ )= 1.2 M

Determine the amount of water that must be added

we will apply the equation below

M₁V₁ = M₂V₂ ---- ( 1 )

where : V₂ = V₁ + water added  ---- ( 2 )

V₂ ( Final volume ) = ( M₁V₁ ) / M₂

                              = ( 6 * 500 ) / 1.2

                              = 2500 mL

Back to eqaution ( 2 )

2500 mL = 500 mL + added water

therefore ; added water = 2500 - 500

                                        = 2000 mL

Hence we can conclude that The amount of water that must be added to 6.0 M silver nitrate to make 500mL of 1.2 M solution is : 2000 mL.

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