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lys-0071 [83]
3 years ago
5

En un experimento hacemos reaccionar 12 g de carbono con 32 g de oxígeno para formar dióxido de carbono. Razona si podemos saber

la cantidad de dióxido de carbono que se forma y en caso afirmativo, calcula la masa obtenida.
Chemistry
1 answer:
max2010maxim [7]3 years ago
5 0

Answer:

La masa de óxido de carbono iv formado es 44 g.

Explanation:

En esta pregunta, se nos pide calcular la masa de óxido de carbono iv formado a partir de la reacción de masas dadas de carbono y oxígeno.

En primer lugar, necesitamos escribir una ecuación química equilibrada.

C + O2 → CO2

De la ecuación, 1 mol de carbono reaccionó con 1 mol de oxígeno para dar 1 mol de óxido de carbono iv.

Ahora, si marca las masas en la pregunta, verá que corresponde a la masa atómica y la masa molar de la molécula de carbono y oxígeno, respectivamente. ¿Qué indica esto?

Como tenemos una relación molar de 1: 1 en todo momento, lo que esto significa es que la masa de óxido de carbono iv producida también es la misma que la masa molar de óxido de carbono iv.

Por lo tanto, procedemos a calcular la masa molar de óxido de carbono iv Esto es igual a 12 + 2 (16) = 12 + 32 = 44 g Por lo tanto, la masa de óxido de carbono iv formado es 44 g

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The following reaction is at equilibrium in a sealed container.
ale4655 [162]

Answer:

D.Lowering the temperature is the best option.

Explanation:

The value of equilibrium constants aren't changed with change in the pressure or concentrations of reactants and products in equilibrium. The only thing that changes the value of equilibrium constant is a change of temperature.

In the reaction below for example;

A + B <==>C+D

If you have moved the position of the equilibrium to the right (and so increased the amount of C and D), why hasn't the equilibrium constant increased?

Let's assume that the equilibrium constant mustn't change if you decrease the concentration of C - because equilibrium constants are constant at constant temperature. Why does the position of equilibrium move as it does?

If you decrease the concentration or pressure of C, the top of the Kc expression gets smaller. That would change the value of Kc. In order for that not to happen, the concentrations of C and D will have to increase again, and those of A and B must decrease. That happens until a new balance is reached when the value of the equilibrium constant expression reverts to what it was before.

3 0
3 years ago
Carbon dioxide and water react to form methanol and oxygen, like this:
fredd [130]

Answer:

24x10³

Explanation:

2CO₂(g) + 4H₂O(g) → 2CH₃OH(l) + 3O₂ (g)

The equilibrium constant for this reaction is:

Kc = \frac{[O_2]^3}{[CO_2]^2[H_2O]^4}

The expression of [CH₃OH] is left out as it is a pure liquid.

Now we <u>convert the given masses of the relevant species into moles</u>, using their <em>respective molar masses</em>:

  • CO₂ ⇒ 3.28 g ÷ 44 g/mol = 0.0745 mol CO₂
  • H₂O ⇒ 3.86 g ÷ 18 g/mol = 0.214 mol H₂O
  • O₂ ⇒ 2.80 g ÷ 32 g/mol = 0.0875 mol O₂

Then we calculate the concentrations:

  • [CO₂] = 0.0745 mol / 7.5 L = 0.0099 M
  • [H₂O] = 0.214 mol / 7.5 L = 0.0285 M
  • [O₂] = 0.0875 mol / 7.5 L = 0.0117 M

Finally we <u>calculate Kc</u>:

  • Kc = \frac{0.0117^3}{0.0099^2*0.0285^4} = 24x10³

3 0
3 years ago
Want ate the five steps of the scientific method
pantera1 [17]

Answer:

make an observation is number one number two is ask a question number three is form a hypothesis number number five isa test the prediction.

6 0
3 years ago
Why is uric acid advantageous for nitrogenous waste excretion in insects? see section 40.4?
Naddika [18.5K]
<span>Answer: Uric acid is advantageous for nitrogenous waste excretion in insects because of low toxicity, excreted.</span>
7 0
3 years ago
What mass of sulfurous acid is produced when 245g of sulfur dioxide is reacted with water?
Nookie1986 [14]

The mass of sulfurous acid produced when 245g of sulfur dioxide is reacted with water is 313.8 g

<h3>Stoichiometry </h3>

From the question, we are to determine the mass of sulfurous acid produced

First, we will write the balaced chemical equation for the reaction

H₂O + SO₂ → H₂SO₃

This means 1 mole of H₂O reacts with 1 mole of sulfur dioxide (SO₂) to produce 1 mole of sulfurous acid (H₂SO₃)

Now, we will determine the number of moles of sulfur dioxide present

Mass of sulfur dioxide present = 245 g

Molar mass of sulfur dioxide = 64.066 g/mol

Using the formula,

Number \ of \ moles = \frac{Mass}{Molar\ mass}

Then,

Number of moles of SO₂ present = \frac{245}{64.066}

Number of moles of SO₂ present = 3.824 moles

This is the number of moles of SO₂ present

From balanced chemical equation

1 mole of H₂O reacts with 1 mole of sulfur dioxide (SO₂) to produce 1 mole of sulfurous acid (H₂SO₃)

Then,

Water (H₂O) will react with the 3.824 moles of sulfur dioxide (SO₂) to produce 3.824 moles of sulfurous acid (H₂SO₃)

∴ The number of moles of sulfurous acid produced is 3.824 moles

Now, for the mass of sulfurous acid produced

Molar mass of sulfurous acid = 82.07 g/mole

Using the formula,

Mass = Number of moles × Molar mass

Mass of sulfurous acid produced = 3.824 × 82.07

Mass of sulfurous acid produced = 313.8 g

Hence, the mass of sulfurous acid produced is 313.8 g

Learn more on Stoichiometry here: brainly.com/question/6061451

8 0
1 year ago
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