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3 years ago

What is pi actual nummber

1 answer:

8 0

If you are using pi in a equation, people normally shorten it to 3.14. But here is the link to the first 100,000 digits of pi: http://www.geom.uiuc.edu/~huberty/math5337/groupe/digits.html

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the temperature in an experiment is increased at a constant rate over a period of time until the temperature reaches 0 degrees c

dsp73

Answer:

x = 28 (So it takes 28 hours for the temperature to reach 0°C.)

y = -70 (So the temperature when the experiment begins is −70°C.)

Step-by-step explanation:

To find the the x value, you remove the y value or replace it with 0.

0 = 5/2x - 70

Next you move the variable.

70 (2/5) = x (multiply 70 by 2 to get 140 and divide that by 5)

And now you simplify to get:

To find the y value, you remove the x value or replace it with 0.

y = 0 - 70

And now you simplify to get:

-70

x = 28

y = -70

7 0

3 years ago

Read 2 more answers

192/38 with remanders

guapka [62]

Answer:

5 Remainder 2

3 0

3 years ago

Read 2 more answers

Plz do number 11. its 5th grade math!

Dmitry [639]

This is division!!
Our answer is ninety six (96)

Have a wonderful weekend
Brooke

8 0

3 years ago

Translate these points

zmey [24]

3,-4 is the correct anwser

3 0

3 years ago

MATH HELP!!! 100PTS!!!

Lostsunrise [7]

Answer:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Step-by-step explanation:

Given functions:

$p(x)=2x-4$

$r(x)=\dfrac{6x-1}{9x+1}$

Solve for p(x) = r(x):

$\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}$

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=18, \quad b=-40, \quad c=-3$

Substitute the values of a, b and c into the quadratic formula and solve for x:

$\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}$

Therefore, the solutions are:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0

2 years ago