Step-by-step explanation:
(x^4)^3=(x^3)^4 , true
=> x^(4×3) = x^(3×4) = x^12
13^4 x 13^7= (13^4)^7, false
13^(4+7) = 13^11
(13^4)^7 = 13^(4×7) = 13^28
y^5 x y^0/y^3=(y^2)^1 , true
y^5 x y^0/y^3 = y^(5+0-3) = y^2
(y^2)^1 = y^(2×1) = y^2
q^0 x q^5/q^2=(q^3)^2/q^3, true
q^0 x q^5/q^2= q^(0+5-2)= q^3
(q^3)^2/q^3 = q^(3×2-3) = q^3
Answer:
The missing value in the solution to
the equation will be:
Step-by-step explanation:
Given the equation

As the value of y = -2 is given.
so substituting the value y = -2 in the equation to find the missing value

switch the sides








Therefore, the missing value in the solution to
the equation will be:
Answer:
<em><u>[</u></em><em><u>2</u></em><em><u>,</u></em><em><u>4</u></em><em><u>,</u></em><em><u>6</u></em><em><u>]</u></em>
Step-by-step explanation:
GIVEN EQUATION : 2X+3≥7
i.e, 2x≥7-3
i.e, 2x≥4
i.e, x≥4/2
i.e, x≥2
it's represent number should be greater than or equal to 2
The only number which follows the inequality from the set is 2,4&6
✌️:)
the solution is here,
the coordinate of centre of circle A is (3,2)
and the coordinate of centre of circle B is (3,0).
so the translation point from A to B is (3-0,0-2)=(3,-2).
Now the translation rule is given by (x+h,y+k)
where h is the tranalation anlong the x-axis and k is the translation along the y-axis.
For this problem, translation ruleis (x+3,y-2).
Then, radius of circle A(r1)=2 units
radius of circle B (r2)= 3 units
as the circle A is translated to B, the scale factor is
r2/r1=3/2=1.5
In conclusion, the translation rule for given circles is (x+3,y-2) and its scale factor is 1.5