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joja [24]
3 years ago
11

Find the rate of change of the area of a square with respect to the length z , the diagonal of the square. what is the rate when

z=2?
Mathematics
1 answer:
Reil [10]3 years ago
4 0
The diagonal of a square is equal to the side x times square root of 2, xSqrt(2)
z = xSqrt(2), its rate of change is just Sqrt(2)
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-2- 3(7-k) =-4(2k-1)
Ivan

Answer:

k=27/11

Step-by-step explanation:

7 0
2 years ago
An analyst must decide between two different forecasting techniques for weekly sales of roller blades: a linear trend equation a
Amiraneli [1.4K]

Answer:

Following are the responses to the given question:

Step-by-step explanation:

Mean Absolute Deviation MAD

MAD = \sum_{i=1}^{n} \frac{\left | actual_{i}-forecast_{i} \right |}{n}

Mean squared error  

MSE=\Sigma^{n}_{i=1} \frac{(Actual_i - Forecast_i)^2}{(n - 1)}

linear trend equation is Ft = 124 + 2t

MAD = \frac{23}{10} = 2.3\\\\MSE = \frac{91}{9}= 10.11\\\\

Naive method

MAD = \frac{36}{9} = 4\\\\MSE = \frac{202}{8}=25.25\\\\MAD (Naive) = 4\\\\MAD (Linear) =2.3\\\\MSE (Naive)=25.25\\\\MSE (Linear)=10.11\\\\

Please find the attached file.

7 0
3 years ago
The length of a rectangle is
Readme [11.4K]

Answer:

Step-by-step explanation:

5 0
3 years ago
Matrix question help needed
kramer

The required matrix is:

\left[\begin{array}{ccc}-25&17&0\\8&-1&3\\\end{array}\right]

Step-by-step explanation:

We need to apply elementary row operation -2R₂+3R₁ tothe matrix:

A=\left[\begin{array}{ccc}-3&5&2\\8&-1&3\\\end{array}\right]

Multiplying Row 2 with -2 and Row1 with 3 and adding,

-9 15 6

-16 2 -6

----------

-25 17  0

After applying this operation, Row 1 will be changed while Row 2 will remain same because we get -2R₂+3R₁ -> R₁

The required matrix is:

\left[\begin{array}{ccc}-25&17&0\\8&-1&3\\\end{array}\right]

Keywords: Matrices, elementary row operation

Learn more about matrices at:

  • brainly.com/question/4464845
  • brainly.com/question/8301701

#learnwithBrainly

6 0
3 years ago
The cost of maintaining car A is $300 per year plus $.014 per mile driven. The cost of maintaining car B is $200 per year plus $
mylen [45]

When cost is equal

\begin{gathered} 300+0.14x=200+0.025x \\ 300-200=0.25x-0.014x \\ 100=0.011x \\ x=\frac{100}{0.011} \\ x=9090.90909091 \\ x=9090.91 \end{gathered}

7 0
11 months ago
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