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anastassius [24]

3 years ago

5

Which algebraic expression is a polynomial with a degree of 5?

1 answer:

barxatty [35]3 years ago

7 0

I hope this’s correct!

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12+22x=-46x I don't know the answer

Arlecino [84]

The answer is

x =<span>‌ <span><span>−3/</span>17</span></span>

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3 years ago

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What is the value of [(2/3)^0]^-3

sleet_krkn [62]

The answer to this question would be 1/8 or in decimal form it would be 0.125. hopefully this helps with your question.

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3 years ago

Find the equation for a parabola if the vertex is 6,9

devlian [24]

The equation for a parabola with vertex (h, k) and vertical scale factor "a" is
y = a(x -h)² + k

One parabola with vertex (6, 9) is
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3 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago

The points in the table lie on a line. Find the slope of the line.

Rina8888 [55]

5/2 or 2.5
Hope this helps!

6 0

3 years ago