Since the square root of a negative number is not a real number, then a negative radical will result in no real solution.
Answer:
x=0, - 9
Step-by-step explanation:
x^2+9x=0
x(x+9)=0
x=0 or x=-9
Answer:
2
Step-by-step explanation:
f(x)=2x^2+9x-5
When we are find how many times it intersects the x axis, we are finding the zero's. Set the equation equal to zero
0=2x^2+9x-5
Factor the equation
0 = (2x+1) (x-5)
2*1
1*-5 = -5
2*-5 +1*1 = -9
This checks for the first last and middle terms so we factored correctly
Then using the zero product property
2x+1 = 0 and x-5 =0
2x = -1 x=5
x = -1/2 and x=5
This function crosses the x axis 2 times
Answer:
B, A
Step-by-step explanation:
In the first equation, if an unknown number plus 17 equals 66, then what step would you take?
For example, if an unknown number plus 2 equaled 3, then you would know that number is 1, right? What steps did you take to get that? You subtracted 2 from both sides.
In this example, if x + 17 = 66, then subtracting 17 from both sides gets us x = 49.
The same applies for the second example. If x minus 54 equals 125, then you would add 54 to get x = 179.
