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4 years ago

11

A bag contains 6 green marbles, 9 red marbles, 7 white marbles, and 3 black marbles. What is the probability of drawing a red ma

rble out of the bag?
A. 1/18

B. 9/16

C. 9/25

D. 1/4

1 answer:

Alla [95]4 years ago

7 0

The answer is <span>C. 9/25.

There are in total 25 marbles:
6 green + 9 red + 7 white + 3 black = 25 marbles.

There are 9 red marbles of the total 25 marbles. You can draw 9 red Thus, the probability of drawing a red marble out of the bag is 9 out of 25, which is 9/25.</span>

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(b)Newton has bought 12 dozen copies in Rs 4320. His expenditure to bring the copies

Alexeev081 [22]

Answer:

30%

Step-by-step explanation:

4320 - 288 = 4032

4032/12 =336 per copies

So, he sold them in 5760

5760 - 4032 = 1728

(1728/5760)*100 = 30%

8 0

3 years ago

You earn $7.50 per hour at a fast food restaurant. You earned $123.75 last week. How many hours did you work last week?

ladessa [460]

I believe you would need to divide 123.75 by 7.50.

The equation would look something like this:
7.50x=123.75
Where x = # of hours worked
123.75 / 7.50 = 16.5
so x = 16.5
You worked for 16.5 hours

3 0

3 years ago

G(x) = 2x – 4<br> h(x)=x²-3<br> Find (g.h)(5)

Mariulka [41]

Answer:

40

Step-by-step explanation:

This is asking you to plug in the value of h(5) into g(x). First solve for h(5)

x^2-3 = h(x)

5^2-3= 22

h(5) = 22

h(5) is 22. So now, plug that into g(x).

g(h(5)) = 2(22)-4

44-4=40

(g.h)(5) is 40.

4 0

3 years ago

Other than 1, what are the perfect square factors for 792? From least to greatest.

Reika [66]

Answer:

Factors of 792: 1, 2, 3, 4, 6, 8, 9, 11, 12, 18, 22, 24, 33, 36, 44, 66, 72, 88, 99, 132, 198, 264, 396, 792. Factor pairs: 792 = 1 x 792, 2 x 396, 3 x 264, 4 x 198, 6 x 132, 8 x 99, 9 x 88, 11 x 72, 12 x 66, 18 x 44, 22 x 36 or 24 x 33.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

I need help please with this 1 problem

Lyrx [107]

Answer:

See below, please

Step-by-step explanation:

We know

$f(x) = {x}^{2} + 3x - 7$

$g(x) = 3x + 5$

$h(x) = 2 {x}^{2} - 4$

Hence

$f(g(x))$

$= {(3x + 5)}^{2} + 3 \times (3x + 5) - 7$

$= (9 {x}^{2} + 30x + 25) + (9x + 15) - 7$

$= 9 {x}^{2} + 39x + 33$

$h(g(x))$

$= 2 \times {(3x + 5)}^{2} - 4$

$2 \times (9 {x}^{2} + 30x + 25) - 4$

$= 18 {x}^{2} + 60x + 50 - 4$

$= 18 {x}^{2} + 60x + 46$

$(h - f)(x)$

$= h(x) - f(x)$

$= (2 {x}^{2} - 4) - ( {x}^{2} + 3x - 7)$

$= {x}^{2} - 3x + 3$

$(f + g)(x)$

$= f(x) + g(x)$

$= ( {x}^{2} + 3x - 7) + (3x + 5)$

$= {x}^{2} + 6x - 2$

5 0

3 years ago