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tankabanditka [31]
3 years ago
5

A flu has hit a city and the percentage of a population with the flu, t days after the disease arrives is approximated by f(t)=1

0te^(-t/8) for 0<=t>=40.
1)after how many days is the percentage of the population with the flu a maximum?
2)what is the maximum percent of the population at this time?
Mathematics
1 answer:
nika2105 [10]3 years ago
4 0
1) To calculate maximum of f(t) function we first need to find derivative of it:
f(t)' = 10(e^(-t/8) + t*e^(-t/8)*(-1/8)) = 10(e^(-t/8) -t/8*e^(-t/8)) = 10e^(-t/8)(1-t/8)

the condition is:
f(t)' = 0 that means:
0 = 10e^(-t/8)(1-t/8) 
10t/8*e*(-t/8) = 10*e^(-t/8)
t/8 = 1
t = 8

The answer is 8 days.

2) that percent we will get simply by expressing t=8 in our equation.
f(8) = 10*8*e^(-1) = 80/e = 29.43%
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A quick search will yield that D(8, 0) and E(4, 0) are definitely adjacent to each other.

Please check the attached file here for a better understanding of the diagram of the original regular hexagon. Points D and E indeed are adjacent to each other.

Let us now find the distance between the points D and E using the distance formula which is as:

d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

Where d is the distance.

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\therefore d=4

We know that this distance is the side length of the given regular hexagon.

\therefore d=a=4

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P_{small}=6a_{small}=6\times 2.4=14.4 unit

Which are the required answers.

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