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lawyer [7]
3 years ago
15

Trigonometry question! find the vaule of x. round to the nearest tenth!​

Mathematics
1 answer:
atroni [7]3 years ago
8 0

Answer:

<h2>x = 88.2</h2>

Step-by-step explanation:

Look at the picture.

Use tangent:

tangent=\dfrac{opposite}{adjacent}

We have a measure of the angle and length of the adjacent:

\alpha=10^o,\ adjacent=500

\tan10^o\approx0.17633

Substitute:

\dfrac{x}{500}=0.17633             <em>multiply both sides by 500</em>

x=88.165\to x=88.2

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AleksandrR [38]

Answer:

R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Step-by-step explanation:

Squaring both sides of equation:

     I^2 = (ER)^2/(R^2 + (WL)^2)

<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)

<=>(ER)^2 - (IR)^2 = (IWL)^2

<=> R^2(E^2 - I^2) = (IWL)^2

<=> R^2 = (IWL)^2/(E^2 - I^2)

<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Hope this helps!

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3 years ago
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