Answer:
it is 8 :)
Step-by-step explanation:
Answer:
1b. 15 plus 16a
2a. 49w plus 28
2b. 36 plus 60n
3a. 50 plus 20w
3b. 77 plus 121a
4a. 55s plus 30
4b. 132 plus 121a
5a. 16 plus 14c
5b. 16q plus 2x ( i dont know about that one )
6a. 21 plus 35r
6b. 88d plus 11k
7a. 132p plus 108
7b. 30b plus 25
Step-by-step explanation:
that took forever
Firstly, solve 38C15.
Then solve 42C12.
Compare your answers.
The goal here is to see if 38C15 = 42C12.
Here is the formula:
nCr = n!/(r!(n - r)!
Go for it.
I think the answer is 14.
the smallest common multiple of 6 and 9 is 18. all multiples of 18 is divisible by 6 and 9.
500 ÷18=27.777777777
there are 27 numbers between 1 and 500 that are divisible by both 6 and 9, but when the quotient is an even number, the multiple of 18 is divisible by 4 as well, so only the multiples of 18 that produce an odd quotient satisfy the requirement.
from 1 to 27, there are 14 odd numbers.
Answer:
B
Step-by-step explanation:
3p+6p+6p=180°
15p=180
p=12
3p=12×3=36°
6p=12×6=72°