The enthalpy of combustion of propane is -2202.0 kJ/mol.
The enthalpy of combustion is released when one mole of compound is burned in the presence of excess oxygen. The bonds between carbon and hydrogen in the compound are broken and bonds between carbon and oxygen are formed as well as bonds between hydrogen and oxygen are formed.
1 yd = 36 in and 1 kg = 1000 g
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It's in the periodic table.
See the attached picture. The number below 'Zn' is the molar mass. The closest answer choice is 65.38
Answer:
1.91 atm
Explanation:
Step 1: Calculate Henry's constant (k)
A gas has a solubility (C) of 2.45 g/L at a pressure (P) of 0.750 atm. These two variables are related to each other through Henry's law.
C = k × P
K = C/P
K = (2.45 g/L)/0.750 atm = 3.27 g/L.atm
Step 2: Calculate the pressure required to produce an aqueous solution containing 6.25 g/L of this gas at constant temperature.
We have C = 6.25 g/L and k = 3.27 g/L.atm. The required pressure is:
C = k × P
P = C/k
P = (6.25 g/L)/(3.27 g/L.atm) = 1.91 atm
