Average atomic mass is =1.11 u
need brainliest
CO₂ does not have dipole-dipole forces as its strongest force.
Draw the 3D structures of each molecule. All have C-O, C-Br, or C-Cl <em>bond dipoles</em>.
In CO₂ the C-O bond dipoles point in opposite directions, so they cancel.
CO₂ has <em>no molecular dipole</em>. Its strongest intermolecular forces are <em>London dispersion forces</em>.
In all the other molecules, the C-Br, C-Cl, and C-O bond dipoles do not cancel. These molecules all have intermolecular dipole-dipole forces.
Answer:
![\Delta G_{rxn} = -50.7 \ kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20G_%7Brxn%7D%20%20%3D%20-50.7%20%5C%20kJ%2Fmol)
Explanation:
The equation of the reaction is given as:
![ATP_{(aq)} + H_2O_{(l)} \to ADP_{(aq)} + HPO_4^{-2}_{(aq)}](https://tex.z-dn.net/?f=ATP_%7B%28aq%29%7D%20%2B%20H_2O_%7B%28l%29%7D%20%5Cto%20ADP_%7B%28aq%29%7D%20%2B%20HPO_4%5E%7B-2%7D_%7B%28aq%29%7D)
Given that:
[ATP] = 5.00 mM
[ADP] = 0.40 mM
[HPO₄²⁻] = 5.00 mM
converting mM to M; we have:
5.00 mM = 5.00 mM × 1 M/ 1000 mM
= 0.005 M
0.40 mM = 0.40 mM × 1 M/ 1000 mM
= 0.0004 M
The equilibrium constant
is:
![K_{eq} = \frac{(0.0004)(0.005)}{(0.005)}](https://tex.z-dn.net/?f=K_%7Beq%7D%20%3D%20%20%5Cfrac%7B%280.0004%29%280.005%29%7D%7B%280.005%29%7D)
= 0.0004
Given that:
![\Delta G^ {^0} _{rxn} =-30.5 \ kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20G%5E%20%7B%5E0%7D%20_%7Brxn%7D%20%3D-30.5%20%5C%20kJ%2Fmol)
To Joule (J) ; we have
![\Delta G^ {^0} _{rxn} =-30.5 \ kJ/mol * \frac{1000 \ J}{1 \ kJ}](https://tex.z-dn.net/?f=%5CDelta%20G%5E%20%7B%5E0%7D%20_%7Brxn%7D%20%3D-30.5%20%5C%20kJ%2Fmol%20%20%2A%20%5Cfrac%7B1000%20%5C%20J%7D%7B1%20%5C%20kJ%7D)
![\Delta G^ {^0} _{rxn} =-30.5 *10^3 \ J/mol](https://tex.z-dn.net/?f=%5CDelta%20G%5E%20%7B%5E0%7D%20_%7Brxn%7D%20%3D-30.5%20%2A10%5E3%20%5C%20J%2Fmol)
Temperature T = 37° C = (37+ 273)K = 310 K
is then calculated by using the equation:
![\Delta G_{rxn} = \Delta G^0 _{rxn}+ RT In \ K_{eq}](https://tex.z-dn.net/?f=%5CDelta%20G_%7Brxn%7D%20%3D%20%5CDelta%20G%5E0%20_%7Brxn%7D%2B%20RT%20In%20%5C%20K_%7Beq%7D)
![\Delta G_{rxn} = (-30.5*10^3 \ J/mol})+ (8.314 \ J/mol.K)(310) \ In \ (0.0004)](https://tex.z-dn.net/?f=%5CDelta%20G_%7Brxn%7D%20%3D%20%28-30.5%2A10%5E3%20%5C%20J%2Fmol%7D%29%2B%20%20%288.314%20%5C%20J%2Fmol.K%29%28310%29%20%5C%20In%20%5C%20%280.0004%29)
![\Delta G_{rxn} = -50.665.23 \ J/mol](https://tex.z-dn.net/?f=%5CDelta%20G_%7Brxn%7D%20%3D%20-50.665.23%20%5C%20J%2Fmol)
![\Delta G_{rxn} = -50.7 \ kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20G_%7Brxn%7D%20%20%3D%20-50.7%20%5C%20kJ%2Fmol)
Since
is negative; the hydrolysis of ATP is spontaneous .
For # 2 1.456• 205 is 1.251 and 2.456 +205 is 298.48
Answer:
You need follower?
See it shows this in Laptop
I can't see who I am following it does itself