Answer: 89
43 + x = 132 => Exterior Angle Theorem
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The measure of an exterior angle of a triangle is greater than either of the measures of the remote interior angles. That means the two remote interior angle add up to the exterior angle.
x = 89
**To find the last angle: 89 + 43 + x = 180 => Triangle Sum Theorem states that the interior angles of a triangle add up to 180. The last angle would be 48.**
It is B that your looking for
First, "boxes of two sizes" means we can assign variables: Let x = number of large boxes y = number of small boxes "There are 115 boxes in all" means x + y = 115 [eq1] Now, the pounds for each kind of box is: (pounds per box)*(number of boxes) So, pounds for large boxes + pounds for small boxes = 4125 pounds "the truck is carrying a total of 4125 pounds in boxes" (50)*(x) + (25)*(y) = 4125 [eq2] It is important to find two equations so we can solve for two variables. Solve for one of the variables in eq1 then replace (substitute) the expression for that variable in eq2. Let's solve for x: x = 115 - y [from eq1] 50(115-y) + 25y = 4125 [from eq2] 5750 - 50y + 25y = 4125 [distribute] 5750 - 25y = 4125 -25y = -1625 y = 65 [divide both sides by (-25)] There are 65 small boxes. Put that value into either equation (now, which is easier?) to solve for x: x = 115 - y x = 115 - 65 x = 50 There are 50 large boxes.
From fraction to decimal: divide the numerator by the denominator
From decimal to percent: move the decimal two places to the right. For example: 0.062=6.2%
From percent to decimal: move the decimal point two steps to the left. For example: 56%=0.56
From decimal to fraction: Rewrite the decimal number number as a fraction (example: <span>2.625=<span>2.6251</span></span>) an then Multiply by 1 to eliminate 3 decimal places, we multiply numerator and denominator by 10 cubed = 1000<span><span><span>2.625/1</span>×<span>1000/1000</span>=<span>2625/1000 and don forget to reduce if possible;)
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Answer:
Horizontal asymptote of the graph of the function f(x) = (8x^3+2)/(2x^3+x) is at y=4
Step-by-step explanation:
I attached the graph of the function.
Graphically, it can be seen that the horizontal asymptote of the graph of the function is at y=4. There is also a <em>vertical </em>asymptote at x=0
When denominator's degree (3) is the same as the nominator's degree (3) then the horizontal asymptote is at (numerator's leading coefficient (8) divided by denominator's lading coefficient (2)) 
