Answer:
Sequence: 13, 20, 27
Rule: Tn = 7n + 6
Step-by-step explanation:
The 3 other numbers that can form an arithmetic progression is 13, 20, 27...
The nth term of an arithmetic progression is expressed as;
Tn = a + (n-1)d
a is the first term = 13
n is the number of terms
d is the common difference = 20 - 13 = 27 - 20
d = 7
Substitute
Tn = 13 + (n-1)(7)
Tn = 13 + 7n - 7
Tn = 7n+13-7
Tn = 7n + 6
This gives the required rule
Answer:
D. 3.2
Step-by-step explanation:
Mid-segment Theorem of a triangle states that the Mid-segment in a triangle is half of the third side of the triangle.
Based on this theorem, we have: TV = ½(RS)
TV = 3n - 2
RS = n + 12
Substitute
3n - 2 = ½(n + 12)
Multiply both sides by 2
2(3n - 2) = (n + 12)
6n - 4 = n + 12
Collect like terms
6n - n = 4 + 12
5n = 16
Divide both sides by 5
5n/5 = 16/5
n = 3.2
I know step 5 is (x-2)(x+2)(x+1)
But I don't know what step 4 is.
Im stuck.
Answer:
The zeros are x=0,3,-2
There is a multiplicity of 1 for all of them.
Step-by-step explanation:
