Answer: Probability of trucks having both defects is 4%.
Step-by-step explanation:
Since we have given that
Probability of trucks having defective brake linings only = 6%
Probability of trucks having defective steering only = 3%
Probability of trucks having neither defect = 87%
Probability of trucks having either defect - 100 - 87 = 13%
Let the probability of trucks having both defects be 'x'.
P(defective brake lining) = P(B) = 0.06+x
P(defective steering) = P(S) = 0.03+x
So, Probability of the trucks having both defects is given by

So, Probability of trucks having both defects is 4%.
Answer:
8
Step-by-step explanation:
Answer:
D, E &F
Step-by-step explanation:
Lets's go down the list and evaluate each choice
A. (3^8) / (3^4) = 3^ (8-4) = 3^4 (≠ 3^2)
B. 6²/2 = (2 x 3)²/2 = (2²·3²)/2 = 4·3²/2 = 2.3² (≠ 3^2)
C. (3^5) ·(3^3) = 3^ (5+3) = 3^8 (≠ 3^2)
D 3·3 = 3^2 (Answer)
E. (3^12) / (3^10) = 3^ (12 -10) = 3^2 (Answer)
F. (3^-3) / (3^-5) = 3^ [ -3 -(-5) ] = 3^ (-3 + 5) = 3^2 (Answer)