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nika2105 [10]
3 years ago
7

Pablo wants to save $800 to buy a TV. He saves $19 each week. The amount, A (in dollars), that he still needs after

Mathematics
2 answers:
Aleks04 [339]3 years ago
8 0

Answer:

a) $686

b) 17 weeks

Step-by-step explanation:

a) Set w=6, as Pablo has already saved for 6 weeks. Plug in the value and solve for A(6).

A(w)=800-19w

A(6)=800-19(6)

A(6)=800-114

A(6)=686

Pablo still needs $686.

b) Set A(w)=477, as it is the "final amount" for that week.  Solve for w.

A(w)=800-19w

477=800-19w

-323=-19w

w=17

Pablo has been saving for 17 weeks if he still needs $477.

Sidana [21]3 years ago
6 0

Answer:

Pablo wants to save $800 to buy a TV.

He saves $19 each week.

The amount, A (in dollars), that he still needs after  weeks is given by the following function.

A(w)= 800-19w

(a) How much money does Pablo still need after 6 weeks?

Putting w = 6 in the equation;

A(6)= 800-19(6)

= $686

(b) If Pablo still needs $477, how many weeks has he been saving?

This means Pablo has already saved 800-477=323 dollars

Means he has saved for \frac{323}{19}=17 weeks.

He has been saving for 17 weeks now.

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Answer:

A. \frac{17}{52}

B. \frac{17}{52}

C. \frac{2}{13}

Step-by-step explanation:

A.

There are 52/4 diamonds in the deck and 4 '5's in the dech of cards

52/4 = 13 + 4 = 17

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There are 13 hearts in the deck and 4 jacks. Therefore, your odds are the same : \frac{17}{52}

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There are 4 jacks in a deck of cards and 4 '8's in a deck of cards

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BRAINLIEST AWARD NO.2
zzz [600]

Answer:

A whole number first term to render as fifth term a value larger than 10000, should be at least 121

Step-by-step explanation:

The formula is given as recursive since it involves the previous number of the sequence, and defined as:

a_n=a_{n-1}*3+6

we also know that the first term is 4

Then in this case, the first five terms are:

a_1=4\\a_2=4*3+6=18\\a_3=18*3+6=60\\a_4=60*3+6=186\\a_5=186*3+6=564\\

So if we want to find the first term in the case that the fifth one is greater than 10,000 using this recursive formula, now we have to start backwards, and say that the fifth term is "> 10000" and what the fourth one is.

Notice that if you have this definition for the nth term, we can obtain from it, what the previous term is to find the general rule:

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a_5>10000\\\frac{a_5}{3} -2>\frac{10000}{3} -2\\a_4>=\frac{10000}{3} -2\\\frac{a_4}{3} -2>\frac{\frac{10000}{3}-2}{3}-2 =\frac{10000}{9}-\frac{8}{3} \\a_3>\frac{10000}{9}-\frac{8}{3} \\\frac{a_3}{3} -2>\frac{\frac{10000}{9}-\frac{8}{3} }{3} -2=\frac{10000}{27} -\frac{8}{9} -2=\frac{10000}{27} -\frac{26}{9}\\a_2=\frac{10000}{27} -\frac{26}{9}\\\frac{a_2}{3} -2>\frac{\frac{10000}{27} -\frac{26}{9}}{3} -2=\frac{10000}{81} -\frac{80}{27} \\a_1>\frac{10000}{81} -\frac{80}{27}\approx 120.49

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